02-22-2012
converting string to number in shell script
Hi,
I am having a problem in converting a string to number so I can preform arithmetic operations.
timeTot=0
timeTmp=$(cat idsOutput | grep 'Run time' | cut -c 36-39)
timeTot=$[$timeTot+$timeTmp] #This is line 28
echo "total RunTime=" $timeTot
this is the error msg:
./ids2.sh: line 28: 0+1.35: syntax error: invalid arithmetic operator (error token is ".35")
total RunTime= 0
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TRAPOV(3F) TRAPOV(3F)
NAME
trapov - trap and repair floating point overflow
SYNOPSIS
subroutine trapov (numesg, rtnval)
double precision rtnval
DESCRIPTION
NOTE: This routine applies only to the older VAX 11/780's. VAX computers made or upgraded since spring 1983 handle errors differently.
See trpfpe(3F) for the newer error handler. This routine has always been ineffective on the VAX 11/750. It is a null routine on the
PDP11.
This call sets up signal handlers to trap arithmetic exceptions and the use of illegal operands. Trapping arithmetic exceptions allows the
user's program to proceed from instances of floating point overflow or divide by zero. The result of such operations will be an illegal
floating point value. The subsequent use of the illegal operand will be trapped and the operand replaced by the specified value.
The first numesg occurrences of a floating point arithmetic error will cause a message to be written to the standard error file. If the
resulting value is used, the value given for rtnval will replace the illegal operand generated by the arithmetic error. Rtnval must be a
double precision value. For example, ``0d0'' or ``dflmax()''.
FILES
/usr/lib/libF77.a
SEE ALSO
trpfpe(3F), signal(3F), range(3F)
BUGS
Other arithmetic exceptions can be trapped but not repaired.
There is no way to distinguish between an integer value of 32768 and the illegal floating point form. Therefore such an integer value may
get replaced while repairing the use of an illegal operand.
4.2 Berkeley Distribution May 15, 1985 TRAPOV(3F)