12-06-2011
how to count number of times each word exist in a file
I'm trying to count the number of times each word in the file exist
for example if the file has:
today I have a lot to write, but I will not go for it. The main thing is that today I am looking for a way to get each word in this file with a word count after it specifying that this word has occured that number of times in the whole file.
today-->2
I-->3
have-->1
a-->3
lot-->1
write-->1
but-->1
will-->1
not-->1
and so on
I used tr to separate each word in a line but I'm not sure how I'm going to look for each word
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LEARN ABOUT DEBIAN
dictfmt_index2word
DICTFMT_INDEX2WORD(1) Linux User's Manaul DICTFMT_INDEX2WORD(1)
NAME
dictfmt_index2word - Creates a .word index file from a DICTD database .index file
SYNOPSIS
dictfmt_index2word [OPTIONS] [index_file]
DESCRIPTION
dictfmt_index2word creates a word index file on stdout for the index file given on stdin or the command line. A word index file indexes
each subword from the multi-word headwords of the .index file, to the underlying .dict file. A word index file is usually named <base-
name>.word, but this is not mandatory as long as the proper name is used in the dictd configuration file.
OPTIONS
--help displays a usage message and exits
--locale locale
use locale for sorting the .word file. If this option is omitted, the default locale "C" is used.
index_file
the .index file to be converted.
AUTHOR
dictfmt_index2word was written by Aleksey Cheusov <vle@gmx.net>.
This manual page was written by Robert D. Hilliard <hilliard@debian.org>.
SEE ALSO
dictd(8), dictfmt(1), dictfmt_index2suffix(1)
LINUX
January 23, 2003 DICTFMT_INDEX2WORD(1)