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Top Forums Shell Programming and Scripting Handling parameters in Shell Functions Post 302402382 by bharath.gct on Tuesday 9th of March 2010 04:56:18 PM
Old 03-09-2010
Handling parameters in Shell Functions

Hi,

Please help me with the below situation where I have to handle the parameters passed to a function in a unique way.

Below is the code, which I am trying to execute. I basically want to pass the parameter to a function, where I am trying to get user input into array(s). I want to name the array(s) based on the parameter. Please help me do it!!

Code:
 
#! /bin/sh
 
#GET_TABLE FUNCTION
get_table()
{
  i=0;
 
  set -A $1_file_array NULL;
  set -A $1_db_array NULL;
  set -A $1_table_array NULL;
 
  echo " Please enter tables that are affected in '<DBName>.<Tablename(s)>' format      :"
 
  while read file
  do
    if [ ${#file} -gt 0 ]; then
      $1_file_array[$i]=$file
      $1_db_array[$i]=${file%.*}
      $1_table_array[$i]=${file#*.}
      i=`expr $i + 1`
    fi
  done
  $1_count=${#$1_file_array[@]}
  return $1_count
}
 
# CALL FUNCTION GET_TABLE WITH 'SRC' AS PARM
get_table src
 
# DISPLAY THE LOADED ARRAY
j=0;
src_count=$?
while [ $j -lt src_count ]
do
# BELOW ARE THE ARRAY NAMES I WISH TO SEE
    echo "File: ${src_file_array[$j]}"
    echo "DB: ${src_db_array[$j]}"
    echo "Table: ${src_table_array[$j]}"
    j=`expr $j + 1`
done

Please let me know for any questions.

Thanks
Bharath
 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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