i have a commad that display the total each directory size in KB.Below the commad and o/p:
ls -ltr | grep ^d | awk '{print $9}' | xargs du -sk
output:
what i want is the proper tab space b/w value and dir.? how to get that.
thanks in advance (10 Replies)
Hello,
Is there a direct command to check if the delimiter in your file is a tab or a space? And how can they be converted from one to another.
Thanks,
G (4 Replies)
Hi All,
Sample records
2157 91128 -rw-r----- 1 arun1 staff 93315072 Aug 23 06:44 /home/arun/my own/file_name.txt
2157 91128 -rw-r----- 1 arun1 staff 93315072 Aug 23 06:44 /home/arun/myown/file name2.txt
i want to print only user name, user group, size, date time stamp, and... (5 Replies)
Hi, I want to read lines from a file, and I'm using two methods
1 use
while read line
do
done<filename
2 use
line=`sed -n '3p' filename`
however, in both of them, I notice that the tab between fields are automatically converted to space
because I want to use awk over the... (10 Replies)
Hi,
I have a space delimited text file but I only want to change the first space to a tab and keep the rest of the spaces intact. How do I go about doing that? Thanks! (3 Replies)
I have a variable sumOfJEOutputFile which is the output file of an SQL command which contains the output of that SQL. The output looks like below:
-----------
58
I am using following code to manipulate the output:
(sed 1,2d $sumOfJEOutputFile > $newTemp1 | sed '$d' $newTemp1)... (4 Replies)
In the below awk the output is space delimited, but it should be tab delimited. Did I not add the correct -F and OFS? Thank you :).
The input file are rather large so I did not include them, but they are tab-delimeted files as well.
awk
awk -F'\t' -v OFS='\t' 'FNR==1 { next }
> ... (2 Replies)
My file looks like
3 33 210.01.10.0 2.1 1211 560 26 45 1298 98763451112 15412323499 INPUT OK
3 233 40.01.10.0 2.1 1451 780 54 99 1876 78787878784 15423210199 CANCEL OK
Aim is to replace the spaces in each line by tab
Used: sed -e 's/ */\t/g'
But I get output like this... (3 Replies)
Discussion started by: sa@@
3 Replies
LEARN ABOUT MOJAVE
lessecho
LESSECHO(1) General Commands Manual LESSECHO(1)NAME
lessecho - expand metacharacters
SYNOPSIS
lessecho [-ox] [-cx] [-pn] [-dn] [-mx] [-nn] [-ex] [-a] file ...
DESCRIPTION
lessecho is a program that simply echos its arguments on standard output. But any metacharacter in the output is preceded by an "escape"
character, which by default is a backslash.
OPTIONS
A summary of options is included below.
-ex Specifies "x", rather than backslash, to be the escape char for metachars. If x is "-", no escape char is used and arguments con-
taining metachars are surrounded by quotes instead.
-ox Specifies "x", rather than double-quote, to be the open quote character, which is used if the -e- option is specified.
-cx Specifies "x" to be the close quote character.
-pn Specifies "n" to be the open quote character, as an integer.
-dn Specifies "n" to be the close quote character, as an integer.
-mx Specifies "x" to be a metachar. By default, no characters are considered metachars.
-nn Specifies "n" to be a metachar, as an integer.
-fn Specifies "n" to be the escape char for metachars, as an integer.
-a Specifies that all arguments are to be quoted. The default is that only arguments containing metacharacters are quoted
SEE ALSO less(1)AUTHOR
This manual page was written by Thomas Schoepf <schoepf@debian.org>, for the Debian GNU/Linux system (but may be used by others).
Send bug reports or comments to bug-less@gnu.org.
Version 487: 25 Oct 2016 LESSECHO(1)