01-06-2009
10 More Discussions You Might Find Interesting
1. UNIX for Advanced & Expert Users
Hi i would like to add line numbers to end of each line in a file.
I am able to do it in the front of each line using sed, but not able to add at the end of the file.
Can anyone suggest
The following code adds line number to start of each line
sed = filename | sed 'N;s/\n/\t/'
how can i... (5 Replies)
Discussion started by: rudoraj
5 Replies
2. Shell Programming and Scripting
write a shell script that accepts a file name starting and ending line numbers as arguments and displays all the lines between the given line numbers:b:.help is appreciated.thank you. (3 Replies)
Discussion started by: shawz
3 Replies
3. Shell Programming and Scripting
Hi All,
I had a file called Input.txt, i need to group up in a single line as 1=ttt and the no of lines may vary bewteen the 1=ttt
cat Input.txt
1=ttt,2=xxxxxx, 3=4545
44545, 4=66667
7777, 5=77723
1=ttt, 2=xxxxxx, 3=34436 66
3545, 4=66666, 5=ffffff, 6=uuuuuuu
1=ttt, 2=xxxxxx,... (4 Replies)
Discussion started by: manosubsulo
4 Replies
4. Shell Programming and Scripting
Hi all,
I have a file consisting of lines in such a format: separated by space and M1 EOS for fullstop (.) ]
e.g
M1 I
M1 have
M1 a
M1 file
M1 consisting
M1 of
M1 lines
M1 in
M1 such
M1 a
M1 format
M1 EOS
M2 This
M2 is
M3 an (4 Replies)
Discussion started by: my_Perl
4 Replies
5. Shell Programming and Scripting
Hi All,
How to get line numbers when we more on a file in LINUX
thanks
firestar (1 Reply)
Discussion started by: firestar
1 Replies
6. UNIX for Dummies Questions & Answers
I know if i use grep -n that the output will have the lines numbered but is there a way to grep the actually line number.
so like this
grep -n "one" /usr/dict/numbers
1:one
21:twenty-one
31:thirty-one
41:forty-one
51:fifty-one
61:sixty-one
71:seventy-one
81:eighty-one
91:ninety-one
... (1 Reply)
Discussion started by: alindner
1 Replies
7. Shell Programming and Scripting
Hi! I'm trying to assign line numbers to each line of the file
for example consider the following..
The contents of the input file are
hello how are you?
I'm fine.
How about you?
I'm trying to get the following output..
1 hello how are you?
2 I'm fine.
3 How about you? ... (8 Replies)
Discussion started by: abk07
8 Replies
8. Shell Programming and Scripting
if i want to display the contents of a file between say line number 3 and 10 then i use the following command
sed -n '3,10p' filename
if this 3 was contained in x and 10 was contained in y then how wud this command modified?
sed -n '$x,$yp' filename does not work..please advise (2 Replies)
Discussion started by: arindamlive
2 Replies
9. UNIX for Dummies Questions & Answers
Hi all,
How can i display the middle line of a file using a single line command? (6 Replies)
Discussion started by: Lakme Pemmaiah
6 Replies
10. UNIX for Dummies Questions & Answers
Hello All,
I am very sure this a dumb question to many, but from my view its worth asking.
When I do a vi on a file, on the right bottom side I am seeing something like below:
27,16-24 7%
which tells me that I am on line 27 (which is the first number before the comma, i would like... (11 Replies)
Discussion started by: babyPen1985
11 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)