07-05-2008
Quote:
Originally Posted by
Arun.Kakarla
Hi,
I want to know how to create a hidden file in linux??
Regards
Arun.Kakarla
# touch .teste
If you want to list them later in a ls command, you may add -a option as:
# ls -a
8 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi. I have a script which is deleting files with a particular extension and older than 45 days.The code is:
find <path> -name "<filename_pattern>" -mtime +45 -exec rm {} \;
But the problem is that some important files are also getting deleted.To prevent this I have decide to make a dummy... (4 Replies)
Discussion started by: pochaw
4 Replies
2. Solaris
Hi all,
I want to get only hidden files(which are start with '.' or '..') information in a current directory. I tried the below command,
$ find . -name "^." -exec ls -la '{}' \;
but it's not working. Can anyone give me your outputs.
Thanks in advance,
Raghu. (5 Replies)
Discussion started by: raghu.iv85
5 Replies
3. UNIX for Dummies Questions & Answers
I usually use ls -al | awk '{sum = sum + $5} END {print sum}' to sum the size of all files in a directory. However this command includes the hidden files.
Is there a command to just add up all the files/sub-directories excluding the hidden files (begins with . and ..)
I wanted to check the... (10 Replies)
Discussion started by: lhareigh890
10 Replies
4. Linux
Hi,
Some porocess is creating hidden temporary files in /tmp directory. And they are not getting deleted. System is going out of disk space after some days.
The temp files are getting created like .<user name><pid>. I have checked the application code, but didnt get any clue. Does these ... (2 Replies)
Discussion started by: viswath.sen
2 Replies
5. UNIX for Dummies Questions & Answers
How to list out only the hidden files from a directory ?
Thanks (4 Replies)
Discussion started by: pandeesh
4 Replies
6. AIX
I have a bunch of hidden files in a directory in AIX. I would like to move these hidden files as regular files to another directory.
Say i have the following files in directory /x
.test~1234~567
.report~5678~123
.find~9876~576
i would like to move them to directory /y as
test~1234~567... (10 Replies)
Discussion started by: umesh.narain
10 Replies
7. UNIX for Advanced & Expert Users
Find all files in the current directory only excluding hidden directories and files.
For the below command, though it's not deleting hidden files.. it is traversing through the hidden directories and listing normal which should be avoided.
`find . \( ! -name ".*" -prune \) -mtime +${n_days}... (7 Replies)
Discussion started by: ksailesh1
7 Replies
8. Shell Programming and Scripting
Hello.
I use this command :
rsync -av --include=".*" --dry-run "$A_FULL_PATH_S" "$A_FULL_PATH_D"The data comes from the output of a find command.
And no full source directories are in use, only some files.
Source example... (2 Replies)
Discussion started by: jcdole
2 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)