hey all,
i made a simple .sh like this:
echo "<style media="screen" type="text/css">@import url("main.css");</style>"
but the output is:
<style media=screen type=text/css>@import url(main.css);</style>
i want to keep double-quotes, can anyone help me?
thanks (3 Replies)
Hi,
I've been trying to write a regex to use in egrep (in a shell script) that'll fetch the names of all the files that match a particular pattern. I expect to match the following line in a file:
Name = "abc"
The regex I'm using to match the same is:
egrep -l '(^) *= *" ** *"$' /PATH_TO_SEARCH... (6 Replies)
Could you please help in unix scripting for below scenario...
In my input file, there might be a chance of having a string ( Ex:"99999") after 5th double quote for each record. I need to replace it with a space.
Ex : Input :
"abcdef","12345","99999","0986"... (3 Replies)
I'm trying to extract a column from a csv file with either cut or awk but some of the fields contain comma with them:
"Field1","Field2, additional info","Field3",...,"Field17",...
If I want to extract column 3 and use comma as the delimiter, I'll actually get the additional info bit but not... (4 Replies)
Can somebody supply me with a simple way to get a value between
two double quotes?
Example:
input = ADR base is "/u01/app/oracle"
output = /u01/app/oracle
Thanks to all who answer (4 Replies)
Hi Froum.
I have tried in vain to find a solution for this problem - I'm trying to replace any double quotes within a quoted string with a single quote, leaving everything else as is.
I have the following data:
Before:
... (32 Replies)
Hi All ,
We have source data file as csv file and since data could contain commas ,each attribute is quoted into double quotes.However problem is that some of the attributa data also contain double quotes which is converted to double double quote while creating csv file
XLs data :
... (2 Replies)
From:
1,2,3,4,5,This is a test
6,7,8,9,0,"This, is a test"
1,9,2,8,3,"This is a ""test"""
4,7,3,1,8,""""
To:
1,2,3,4,5,This is a test
6,7,8,9,0,"This; is a test"
1,9,2,8,3,"This is a ''test''"
4,7,3,1,8,"''"Is there an easy syntax I'm overlooking? There will always be an odd number... (5 Replies)
Hi,
I am wanting to create a script that will construct a SQL statement based on a a space delimited string that it read from a config file.
Example of the SQL will be
For example, it will read a string like "AAA BBB CCC" and assign to a variable named IN_STRING.
I then concatenate... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT PHP
ziparchive.addfile
ZIPARCHIVE.ADDFILE(3) 1 ZIPARCHIVE.ADDFILE(3)ZipArchive::addFile - Adds a file to a ZIP archive from the given path
SYNOPSIS
bool ZipArchive::addFile NULL (string $filename, [string $localname], [int $start], [int $length])
DESCRIPTION
Adds a file to a ZIP archive from a given path.
PARAMETERS
o $filename
- The path to the file to add.
o $localname
- If supplied, this is the local name inside the ZIP archive that will override the $filename.
o $start
- This parameter is not used but is required to extend ZipArchive.
o $length
- This parameter is not used but is required to extend ZipArchive.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
This example opens a ZIP file archive test.zip and add the file /path/to/index.txt. as newname.txt.
Example #1
Open and add
<?php
$zip = new ZipArchive;
if ($zip->open('test.zip') === TRUE) {
$zip->addFile('/path/to/index.txt', 'newname.txt');
$zip->close();
echo 'ok';
} else {
echo 'failed';
}
?>
NOTES
Note
When a file is set to be added to the archive, PHP will lock the file. The lock is only released once the ZipArchive object has
been closed, either via ZipArchive::close or the ZipArchive object being destroyed. This may prevent you from being able to delete
the file being added until after the lock has been released.
PHP Documentation Group ZIPARCHIVE.ADDFILE(3)