Hello,
I am new to unix and would like to have a count of all the files in the current directory as well as all the files in a subdirectory.
The command I used was ls -R | wc -l
but the number returned wasn't correct. Can someone please help?
Thanks (2 Replies)
Hello, I'm trying to create a BASH file that can read all the files in my working directory and tell me how many words and lines are in that file. I wrote the following code:
FILES="*"
for f in "$FILES"
do
echo -e `wc -l -w $f`
done
My issue is that my file is outputting in one... (4 Replies)
how to count the total number of lines of all the files under a directory using perl script..
I mean if I have 10 files under a directory then I want to count the total number of lines of all the 10 files contain. Please help me in writing a perl script on this. (5 Replies)
Hi,
Please let me know how to find out number of files in a directory excluding existing files..The existing file format will be unknown..each time..
Thanks (3 Replies)
Hi!
In our current directory there are around 35000 files.
Out of these a few thousands(around 20000) start with, "testfiles9842323879838".
I want to count the number of files that have filenames starting with the above pattern. Please help me with the command i could use.
Thank... (7 Replies)
Hi!
I just want to count number of files in a directory, and write to new text file, with number of files and their name
output should look like this,,
assume that below one is a new file created by script
Number of files in directory = 25
1. a.txt
2. abc.txt
3. asd.dat... (20 Replies)
hi I am trying to write a script to count the number of files, with slightly different subset name, in a directory
for example, in directory /data, there are a subset of files that are name as follow
/data/data_1_(1to however many).txt
/data/data_2_(1 to however many).txt... (12 Replies)
Hi All!
I need to have a script that counts the number of files arriving in a landing directory, them some app pick these files to be processed and load to a DB. But this process is so fast that I am not able to count all the files arriving on a landing directory.
Please can you help?
My... (6 Replies)
I have a directory of files, each with a variable (though small) number of lines. I would like to go through each line in each file, and print the:
-file name
-line number
-number of matches to the pattern /comp/ for each line.
Two example files:
cat... (4 Replies)
Discussion started by: pathunkathunk
4 Replies
LEARN ABOUT REDHAT
zipgrep
ZIPGREP(1L)ZIPGREP(1L)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 17 February 2002 ZIPGREP(1L)