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Top Forums Shell Programming and Scripting How to delete trailing zeros from a variable Post 302118659 by anbu23 on Wednesday 23rd of May 2007 11:56:07 AM
Old 05-23-2007
Quote:
Originally Posted by Chandu2u
i tried with above solution bt if variable has 1234 den it is returning null bt i want as 1234 it self
Code:
$ echo 1234  | awk ' { sub("\\.*0+$","");print} '
1234

 

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lprm(1) 							    Apple Inc.								   lprm(1)

NAME
lprm - cancel print jobs SYNOPSIS
lprm [ -E ] [ -U username ] [ -h server[:port] ] [ -P destination[/instance] ] [ - ] [ job-id(s) ] DESCRIPTION
lprm cancels print jobs that have been queued for printing. If no arguments are supplied, the current job on the default destination is canceled. You can specify one or more job ID numbers to cancel those jobs or use the - option to cancel all jobs. OPTIONS
The lprm command supports the following options: -E Forces encryption when connecting to the server. -P destination[/instance] Specifies the destination printer or class. -U username Specifies an alternate username. -h server[:port] Specifies an alternate server. CONFORMING TO
The CUPS version of lprm is compatible with the standard Berkeley command of the same name. EXAMPLES
Cancel the current job on the default printer: lprm Cancel job 1234: lprm 1234 Cancel all jobs: lprm - SEE ALSO
cancel(1), lp(1), lpq(1), lpr(1), lpstat(1), CUPS Online Help (http://localhost:631/help) COPYRIGHT
Copyright (C) 2007-2017 by Apple Inc. 22 May 2014 CUPS lprm(1)
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