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Full Discussion: handling date field
Top Forums Shell Programming and Scripting handling date field Post 302113138 by cfajohnson on Tuesday 3rd of April 2007 06:00:19 PM
Old 04-03-2007
Quote:
Originally Posted by mgirinath
Is there any way we could change the date format listed below...

date I get is 03302007 (MMDDYYYY)
I need to change it to 20070330 (YYYYMMDD)

Separate the components, then put them back together in the order you want:

Code:
date=03302007
temp=${date#??}
month=${date%"$temp"}
day=${temp%????}
year=${temp#??}
newdate=$year$month$day

 

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DATE_PARSE_FROM_FORMAT(3)						 1						 DATE_PARSE_FROM_FORMAT(3)

date_parse_from_format - Get info about given date formatted according to the specified format

SYNOPSIS
array date_parse_from_format (string $format, string $date) DESCRIPTION
Returns associative array with detailed info about given date. PARAMETERS
o $format - Format accepted by DateTime.createFromFormat(3). o $date - String representing the date. RETURN VALUES
Returns associative array with detailed info about given date. EXAMPLES
Example #1 date_parse_from_format(3) example <?php $date = "6.1.2009 13:00+01:00"; print_r(date_parse_from_format("j.n.Y H:iP", $date)); ?> The above example will output: Array ( [year] => 2009 [month] => 1 [day] => 6 [hour] => 13 [minute] => 0 [second] => 0 [fraction] => [warning_count] => 0 [warnings] => Array ( ) [error_count] => 0 [errors] => Array ( ) [is_localtime] => 1 [zone_type] => 1 [zone] => -60 [is_dst] => ) SEE ALSO
DateTime.createFromFormat(3), checkdate(3). PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)
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