04-11-2006
hi
try this
ls -lg | awk '//
{
if(length($7)==4)
{
print $8,$7
}
else
{
print $8, system("date +%Y")
}
}'
it will prints file name and year - if exists otherwise it will print
file name and current year.
it also returns ls -lg output i dont know how to avoid that
might be someone from foroum willhelp us
regards,
swapneel
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cal(1) General Commands Manual cal(1)
NAME
cal - print calendar
SYNOPSIS
[[month] year]
DESCRIPTION
prints a calendar for the specified year. If a month is also specified, a calendar just for that month is printed. If neither is speci-
fied, a calendar for the present month is printed. year can be between 1 and 9999. month is a decimal number between 1 and 12. The cal-
endar produced is a Gregorian calendar.
EXTERNAL INFLUENCES
For information about the UNIX Standard environment, see standards(5).
Environment Variables
determines the locale to use for the locale categories when both and the corresponding environment variable (beginning with do not specify
a locale. If is not set or is set to the empty string, a default of "C" (see lang(5)) is used.
determines the locale for interpretation of sequences of bytes of text data as characters (e.g., single- verses multibyte characters in
arguments and input files).
determines the format and contents of the calendar.
determines the timezone used to calculate the value of the current month.
If any internationalization variable contains an invalid setting, behaves as if all internationalization variables are set to "C". See
environ(5).
International Code Set Support
Single- and multi-byte character code sets are supported.
EXAMPLES
The command:
prints the calendar for September, 1850 on the screen as follows:
However, for UNIX Standard (see standards(5)), the output looks like below:
WARNINGS
The year is always considered to start in January even though this is historically naive.
Beware that refers to the early Christian era, not the 20th century.
SEE ALSO
standards(5).
STANDARDS CONFORMANCE
cal(1)