08-28-2002
awk - treat multiple delimiters as one
Is there anyway to get awk to treat multiple delimiters as one? Particularly spaces...
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bla bla bla bla bla
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7 PAIXEM 0 7 1 -9 1 0 2 0 1 2 2 1 0 2
9 PAKZXY 0 2 1 -9 2 0 1 1 1 0 1 2 0 1
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awk 'BEGIN{OFS=","} FNR == 1
{if (NR > 1) {print fn,fnr,nl}
fn=FILENAME; fnr = 1; nl = 0}
{fnr = FNR}
/UNUSUAL/ && /\.gz/ ~ /FILENAME/ {nl++}
<'{system ("gunzip -cd FILENAME")}'
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recrod Delimeter count is 10
so 69-10=59
this script will add upto 59 Delimiters to that records.
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CUT(1) General Commands Manual CUT(1)
NAME
cut - select out columns of a file
SYNOPSIS
cut [ -b | -c] list [file...]
cut -f list [-d delim] [ -s]
OPTIONS
-b Cut specified bytes
-c Select out specific characters
-d Change the column delimiter to delim
-f Select out specific fields that are separated by the
-i Runs of delimiters count as one
-s Suppres lines with no delimiter characters, when used
EXAMPLES
cut -f 2 file # Extract field 2
cut -c 1-2,5 file # Extract character columns 1, 2, and 5
cut -c 1-5,7- file # Extract all columns except 6
DESCRIPTION
[file...]" delimiter character ( see delim)" with the -f option. Lines with no delimiters are passwd through untouched"
Cut extracts one or more fields or columns from a file and writes them on standard output. If the -f flag is used, the fields are sepa-
rated by a delimiter character, normally a tab, but can be changed using the -d flag. If the -c flag is used, specific columns can be
specified. The list can be comma or BLANK separated. The -f and -c flags are mutually exclusive. Note: The POSIX1003.2 standard requires
the option -b to cut out specific bytes in a file. It is intended for systems with multi byte characters (e.g. kanji), since MINIX uses
only one byte characters, this option is equivalent to -c. For the same reason, the option -n has no effect and is not listed in this man-
ual page.
SEE ALSO
sed(1), awk(9).
CUT(1)