Hi,
Is there any way we could change the date format listed below...
date I get is 03302007 (MMDDYYYY)
I need to change it to 20070330 (YYYYMMDD)
Thanks. (3 Replies)
:cool:
Hi all,
I have a pecular issue in sorting these files in Solaris environment.
All the below files are modified on November 4th, but I want to sort these files as per date column (eg: 01May07_1623 = ddmmmyy_hhmm)
Nov 4 18:27 SONYELEC00.GI22973.01May07_1623.gpg
Nov 4 18:27... (4 Replies)
Hi Guys,
I'm having a bit of a problem with a script, i need to get the day, month and day of month into a string, so i'm using:
CURRENT_DATE=`date +"%a %b %e"`
It is getting the correct date out, however it is not keeping the padding on the day of month. The %e is supposed to pad the day... (5 Replies)
I have a data file. Seperated by "|". The 19 th filed is a date field that occurs like this
11/02/2001
i need to convert into the below format
2001-11-02
for e.g..
i/p
o/p should be
can somebody throw some light (5 Replies)
from this input
WEBELSOLAR,29122009,1:1
WIPRO,15062010,2:3
ZANDUREALT,18012007,1:3
i want output as
WEBELSOLAR,20091229,1:1
WIPRO,20100615,2:3
ZANDUREALT,20070118,1:3
basically input is in ddmmyyyy format and i was to convert it to yyyymmdd format (1 Reply)
Hi,
In a field, I should receive the date with time stamp in a particular field. But sometimes the vendor sends just the date or the timestamp or correctl the date×tamp. I have to figure out the the data is a date or time stamp or date×tamp.
If it is date then append "<space>00:00:00"... (1 Reply)
I have a .CSV file (file.csv) whose data are all enclosed in double quotes. Sample format of the file is as below:
column1,column2,column3,column4,column5,column6, column7, Column8, Column9, Column10
"12","B000QRIGJ4","4432","string with quotes, and with a comma, and colon: in... (3 Replies)
Hii
I am trying to remove the date field from the following string. ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT. My output should be ODS_EPP_COVRG_STN_DETL_FILE.TXT
I tried couple of things:
echo ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT|sed 's/_*\.*//g'
I am getting:... (9 Replies)
Hi,
Am performing a find based on filename and result can contain multiple files being found
Let's say my find command is
find /Archive -f -name 12345.pdf
and result of find command is
/Archive/Folder A/12345.pdf
/Archive/Folder B/12345.pdf
please note white space in folder names
I... (2 Replies)
Discussion started by: gigagigosu
2 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)