Filename output in curl

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# 1  
Filename output in curl

How can I get the name of the default output filename from curl using the argument -O?

Using -o one can choose a filename. I want to get the name of the original file, but don't understand how to get it.

curl -o filename

curl -O

The only way I know is an insufficient one using the last changed file with the command ls -lat
# 2  
Not sure what keeps you from trying what you already have in your post. What be its result? man curl (linux):
Write output to a local file named like the remote file we get. (Only the file part of the remote file is used, the path is cut off.)
The remote file name to use for saving is extracted from the given URL, nothing else.
Consequentially, the file will be saved in the current working directory. If you want the file saved in a different directory, make sure you change current working directory before you invoke curl with the -O/--remote-name flag!
You may use this option as many times as the number of URLs you have.

This option changes the default action for all given URLs to be dealt with as if -O/--remote-name were used for each one. So if you want to disable that for a specific URL after --remote-name-all has been used, you must use "-o -" or --no-remote-name. (Added in 7.19.0)
# 3  
I want to extract the name itself to a variable. The -O option doesn't do that. I can't attach the name to a variable because I don't know it.

I'm not sure if the ls -lat is a good way.
# 4  
How about

curl -vO |& grep GET

Make sure you specify a remote filename to avoid receiving an error.
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