Passing variable from PHP to bash script

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# 1  
Old 12-08-2017
Passing variable from PHP to bash script

I am totally new to PHP and I am trying to create a script that will as a user for a hostname and then use the "hostname" variable to generate a report using REST API.

I am able to create the html script and php script to GET the "hostname" but I am having trouble passing the hostname variable to the bash script which generates the report using REST API.

This is the html script

<form action="test.php" method="get">
Enter Hostname: <input type="text" name="hostname"><br>
<input type="submit">


This is my php script

Hostname to Query is <?php echo $_GET["hostname"];

$hostname = $argv[1];

#echo "This is $hostname\n";

#$result = shell_exec('/var/www/html/scripts/REST-API/ ' . $hostname);
$result = shell_exec('/var/www/html/scripts/REST-API/ ' . $hostname);

echo $result;


---------- Post updated at 12:38 PM ---------- Previous update was at 12:33 PM ----------

if I do the following from the command line it passes the "hostname" variable to the bash script dpa_report.h script fine. But when I submit the "hostname" from my browser it does not pass the variable...

this command line works

php test.php hostname-test

# 2  
Old 12-08-2017
php variable $hostname is undefined.


Assuming that you are using Apache as the web server, you can do the following:
Start an additional terminal window, and run "tail -f /var/log/apache2/error.log". You will get al running list of errors from your web development.
# 3  
Old 12-08-2017
Thank jgt That fixed that particular problem. Now I am getting a curl error though. If I run the curl from the command line I have no issue but when it is called from the php script which calls the bash script I get this error

curl: (7) Failed to connect to Permission denied

The curl command works fine when I do it from the command line.

Any idea why this is happening?

---------- Post updated at 03:36 PM ---------- Previous update was at 03:34 PM ----------

This is the curl command (I have taken out the username and password

curl -u usernameSmilieassword http://seieadpa01:9004/apollo-api/no...%3dseiemccli01

---------- Post updated at 03:38 PM ---------- Previous update was at 03:36 PM ----------

sorry I never put code around

curl  -u username:password http://seieadpa01:9004/apollo-api/nodes/?query=name%3dhostname

# 4  
Old 12-08-2017
Are the username and password literals, and can you post the balance of the script that includes the curl statement?
# 5  
Old 12-08-2017
This the bash script ( that creates the REST -API report. I have taken out the actual username and password for the purposes of this post. If I run this script from the command line and pass it the hostname it works. For example

./dpa_report hostname

works. The hostname is set to $1 in the script.

But when is called from the php script I get the permission errors.


export HOME=/var/www/html/scripts/REST-API
export TEMP_DIR=/var/www/html/scripts/REST-API/Temp

curl  -u "username:password" http://seieadpa01:9004/apollo-api/nodes/?query=name%3d$1 > $TEMP_DIR/test_file.txt

HOST_ID=`cat $TEMP_DIR/test_file.txt | grep "<id>"`

cat $HOME/host_query_input_file.out | awk -v ID="$HOST_ID" '{if ($1~/\<id>/) $1=ID ;print}' > $TEMP_DIR/host_query_input_file.out

curl -u username:password -X POST -H "Content-Type:application/vnd.emc.apollo-v1+xml" --data "@/var/www/html/scripts/REST-API/host_query_input_file.out" http://seieadpa01:9004/dpa-api/report -o $TEMP_DIR/test_xml.out

LINK=$(grep link $TEMP_DIR/test_xml.out)

export LINK

sleep 5

curl -u username:password $LINK > /var/www/html/REPORTS/$1.html

# 6  
Old 12-08-2017
echo $1 >>/tmp/test.log

ahead of the curl statement
# 7  
Old 12-08-2017
I actually had that in there earlier and it does write to that file with the hostname. the hostname I have been using for testing is seiemccli01

This is the file entry after I run ( is the apache web server)


[root@seinwnprd02 html]# cat /tmp/test.out
[root@seinwnprd02 html]#

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