Need Help on query

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# 1  
Data Need Help on query

I just started to learn unix -

need help to write a script to query a logfile and produce the results that
contains a specific word "alarm" for a period from X day to Y day.

I really have no idea how to begin - Smilie

please help...


# Print out XXX statistics
# Usage


[ $# = 1 ] && { FILE=$FILE.$1 ; }
#echo "LEGEND: DN-Down ; UP-Up ; DS-Disconnected ; AL-Alert ; FL-Failed\n"
#echo "Device ID DN | UP | DS | AL| FL| Device ID DN | UP | DS | AL| FL|"
#echo "===============|====|====|===|===| ===============|====|====|===|===|"

cat $FILE | awk '

/Alert/ {
spos = index($0,"[") + 1
epos = index($0,"]")
LEN = epos - spos
DEV = substr($0,spos,LEN)

if ( index($0,"Low") ) {

for (i in dev ) {
printf "%-10s %4s \n", i, devalert[i]
} '

Last edited by snipfer; 01-15-2009 at 01:21 AM..
# 2  
Hi snip,

You can start with this:

ls | while read $file_to_read
	grep -sin "alarm" $file_to_read

Just modify it a little. You can use a combination of find, ls, or grep and you'll finally get there Smilie

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In bash, grep -v -e '^[[:space:]]*$' file.txt will filter all the blank lines from file.txt and save the results in a file called file.txt.
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