UNIX for Dummies Questions & Answers

Hi, I need to change military time to regular time. I know to use case to indicate whether a.m. or p.m. as follows:

case "$hour"
in
0? | 1[01] ) echo a.m.;;
1[2-9] ) echo p.m.;;
* ) echo p.m.;;
esac

My question is how do I add the hour and minute before the a.m. or p.m.?
I have tried and if statement but I can't cat the two together.
Thanks, in advance,
karp3158

The easiest way is to prepare a variable first and output this once you are done:

Code:

mytimevar="$hour"

case "$hour"
in
        0?  |  1[01] ) mytimevar="$mytimevar a.m.";;
        1[2-9]       ) mytimevar="$mytimevar p.m.";;
        *            ) mytimevar="$mytimevar p.m.";;
esac

print - "$var"

I hope this helps.

bakunin

PS: notice that "print" is a ksh built-in command. If you use Korn shell, you should preferably use "print" instead of "echo", if you use bash change the "print -" to "echo" as bash has no "print" command.

This makes perfect sense !
Thank you for the quick reply.
karp3158