UNIX for Dummies Questions & Answers

I am doing some training for a job I have just got and there is an exercise I am stuck with. I am not posting to ask a question about logic, just a trivial help with string manipulation. I would appreciate if somebody could at least give me a hint on how to do it.

Basically, the intelligent part is all done.
All I have left to do is to replace the user name with the real name

user name: name.surname
real name has to be Name Surname.

I can't use AWK or SED. Any idea?

Thanks

With GNU sed (or ssed) and Perl:

Code:

$ print name.surname | sed -r 's/([^.]*)\.(.*)/\u\1 \u\2/'
Name Surname
$ print name.surname | perl -pe's/(.*?)\.(.*)/\u$1 \u$2/'  
Name Surname

With Z Shell:

Code:

$ n=name.surname
$ print ${(Cs:.:)n}      
Name Surname

Thanks for that, and jees, you were quick!

However, forgot to mention, I am using - have to use - bash.
I tried all the three methods even the AWK one which we are not allowed to use, but I always get this error message:

print: command not found

Try echo instead.

This is what I am typing in:

n=name.surname
echo ${(Cs:.: )}

Result:

-bash: ${(Cs:.: )n}: bad substitution


: and ) have no space between them, edited it because I was getting a smiley...

That one will work only with zsh.
You said AWK is not allowed ..., is this a homework?
If yes, read the rules, if not, please explain where the string is coming from: an input file, a shell variable?

I mentioned it in the original post - an exercise for the training of a job i have just got. As in really, not making it up.
I can't use AWK, and, unfortunately, I can't use Java either, which is what the job is really about.
The logic of the exercise is sorted, it's just the substitution of the string I have got left.

The string comes from a list of users found in a file called passwd.