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print the line immediately after a regexp; but regexp is a sentence


 
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# 1  
Old 11-12-2008
print the line immediately after a regexp; but regexp is a sentence

Good Day,

Im new to scripting especially awk and sed. I just would like to ask help from you guys about a sed command that prints the line immediately after a regexp, but not the line containing the regexp.
sed -n '/regexp/{n;p;}' filename

What if my regexp is 3 word or a sentence. Im using date as my starting point for my logs because its based on a tail alert log that updates daily. sample of it is below:

Completed: ALTER DATABASE RECOVER CANCEL
Starting ORACLE instance (normal)
Thu Nov 13 12:41:34 2008
alter database mount standby database
ORA-1100 signalled during: alter database mount standby database...
Thu Nov 13 12:41:34 2008
ALTER DATABASE RECOVER standby database
Media Recovery Start
ORA-279 signalled during: ALTER DATABASE RECOVER standby database ...
Thu Nov 13 12:41:36 2008
ALTER DATABASE RECOVER CONTINUE DEFAULT
Thu Nov 13 12:41:36 2008
Media Recovery Log /oracle/P03/oraarch/P03arch1_7314.dbf
Thu Nov 13 12:42:15 2008
ORA-279 signalled during: ALTER DATABASE RECOVER CONTINUE DEFAULT ...
Thu Nov 13 12:42:15 2008
ALTER DATABASE RECOVER CONTINUE DEFAULT
Thu Nov 13 12:42:15 2008
Media Recovery Log /oracle/P03/oraarch/P03arch1_7315.dbf

Hope you could help me out because im really stuck here for my script.Smilie
# 2  
Old 11-12-2008
Try:
Code:
sed -n '/Thu Nov 13 /{n;p;}'  filename

Output:

Quote:
alter database mount standby database
ALTER DATABASE RECOVER standby database
ALTER DATABASE RECOVER CONTINUE DEFAULT
Media Recovery Log /oracle/P03/oraarch/P03arch1_7314.dbf
ORA-279 signalled during: ALTER DATABASE RECOVER CONTINUE DEFAULT ...
ALTER DATABASE RECOVER CONTINUE DEFAULT
Media Recovery Log /oracle/P03/oraarch/P03arch1_7315.dbf
# 3  
Old 11-15-2008
thank you very much. i'd really appreciate the help. I got your idea and revised my approach to get my data and surely is aleviating. anyway, thanks.!Smilie
# 4  
Old 11-16-2008
you can do the same thing with awk also
Code:
awk 'c-->0;/pattern/{c=1}' filename

 

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