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Please help me with this simple script

 
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Top Forums UNIX for Dummies Questions & Answers Please help me with this simple script
# 1  
Old 11-05-2008
Please help me with this simple script
Hello,

I'm new to unix but i would like to learn it step by step. Looks more complicated than php but i still want to give it a try.

I want to write a script to print the number and the value of the variables that match the string written from the keyboard.

I know how to do it in PHP and here is the code. Some tips would be usefull.

Thank you in advance.

The PHP looks like this:

Code:
I want to write a script to print the number and the value of the variables that match the string written from the keyboard.

Number of variables that appear in the string is 3.
Variables that appear in the string are: write, script, print

PHP Code:
<?php
//The string
$string= "I want to write a script to print the number and the value of the variables that match the string written from the keyboard.";

//Print the string
echo $string;

// Add the <br /> tag to look nice
echo "<br /><br />";

//This is the array with the words
$array = array("write","script","print","i dont exist");

//With the string, we can split it into a array, with each element containing a different word. We use the explode function for this.
$split = explode(" ", $string);

//This is the number of words found variable, if we find a word we can add 1 to it.
$numWordsFound = 0;

//This array will store the found words.
$wordsFound = array();

//Now we need to loop through all the words in the $split array. We can do this with a foreach() loop
foreach($split as $word){
    //Now we need to check if $word is in the $vars array of words.
    if(in_array($word, $array)){
        //Yes, the word is in.
        //Add it to the words found array.
        $wordsFound[] = $word;
        
        //Now add 1 to the number of words found.
        $numWordsFound += 1;
    }
}

//Now display the information. We use the implode() function on the $wordsFound array to seperate each element with a comma.
echo "Number of variables that appear in the string is " . $numWordsFound . ".<br>";;
echo "Variables that appear in the string are: " . implode(", ", $wordsFound) . ".";
?>
Last edited by Blue; 11-05-2008 at 10:06 AM..
# 2  
Old 11-05-2008
This is what i done so far.

#!/bin/bash
# The string
STRING="Write a script to print the number and the value of the variables that match the string written from the keyboard"

# Print the string
echo $STRING

# This is the array with the words
declare -a ARRAY
ARRAY=( 'print' 'script' 'test' )

# Print ARRAY all elements.
echo ${ARRAY[@]:0}

I dont know how to convert the string into arrays to find the words that exist in the string.

Thank you.
# 3  
Old 11-05-2008
I'm not understanding what the requirement is -
do you ask for input
1. get a word
2. get a string
then search the string for the word?

FWIW - We don't support homework on the forums, and this seems like something a prof would assign....
# 4  
Old 11-05-2008
Thanks for your replay.

No its not a homework, one of my job collegue is learning Unix at school.
I saw this problem and wanted to make the program in php as i dont know unix, linux.

I made it in php and then i was wondering how do you make it for linux, unix ?

End yes that is exactly what i want:

1. get some words
2. get a string
then search the string for the words and print only the one that appear in the string.

I know is not hard but i didnt found it anywhere in some tutorial or something.
I need some tips, its not a homework i finished high school some time ago Smilie but is something that is bothering me and i dont think i will sleep good at night till i find the solution.

Many thanks
# 5  
Old 11-05-2008
I would suggest you read the man pages (man <command>) of the 2 following command for a start, it may inspire you...
read
wc


Regards
# 6  
Old 11-07-2008
I figured out after some reading.

#!/bin/bash
read V
LIST=` printenv |less |grep ".*$V.*" |wc

But i didnt figured out how do i print the variables?

Thanks.
# 7  
Old 11-07-2008
?
Code:
#!/bin/bash
echo " Enter string to match :"
read V

#LIST=` printenv |less |grep ".*$V.*" |wc # What is all this?
# You now have to look through your file or what so lets say a file called in variable INFILE:
 cat $INFILE |grep $V |wc

Why use less? what for?
If this works and are happy with it, then I imagine your idea was to put it also in a variable LIST, but look you forgot the end `
then to print its just echo $LIST
 
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