UNIX for Dummies Questions & Answers

Hi,

I have a directory with a couple of thousand logs in it. The log files are created every 5 minutes. I want to search these logs grep for a specific sting and more importantly print the name of the files where that sting was found.

e.g.

all logs begin om20020927

what I have been doing is

cat OM20020927* |grep 'BalDeductError 6'

That returns the instance of the string, but nt the files that is is found in.

Any help greatly apreciated.

W

You can use grep only

>> grep 'BalDeductError 6' OM20020927*

Now it will show the filename infront of each string found

cd to the directory with your logs in & do this

find . -name "om20020927*" -print | xargs grep "'BalDeductError 6'" > grep.log

grep.log will then contain a list of all matches in your logs which contain "om20020927"

If you re-read man about util grep,
you type something like this:


[def]$ grep "BalDeductError 6" om20020927*




--
Sincerely,
Andrew A.Romanchenko
AlarIT programmer
http://www.AlarIT.com

Check your man page. Some versions of grep allow you to specify the "-l" flag to only printer the file name... See if you have that.