UNIX for Dummies Questions & Answers

hi guys im new here, would like to ask what is the syntax or how could i check the total allocated external disk in HP-UX???

ive check the allocated size using SAM, but in some servers the SAM hangs when checking the disk space. So i would like to know using command line.

thanks

Because of multi-pathing it may not be very straightforward. Are you using Veritas Volume Manager or LVM to manage these disks? If so, it may be best to use the utilities provided with those volume managers to collect the information.

If there is no multipathing you could use something like this:

Code:

ioscan -fun | awk '$1=="disk" && !/ROM/{getline;print "diskinfo -v "$2}' | sh | awk '/size:/{print;tot+=$2} END { print "total: " tot }'

But I can't vouch for the accuracy of the results. You really need to have a fairly intimate knowledge of the storage that your system is attached to to know how to calculate the free space.

diskinfo: Character device required
diskinfo: Character device required
size: 104857600 Kbytes
diskinfo: can't SIOC_INQUIRY /dev/rdsk/c18t0d1: I/O error
size: 104857600 Kbytes
diskinfo: can't SIOC_INQUIRY /dev/rdsk/c19t0d1: I/O error
size: 104857600 Kbytes
diskinfo: can't SIOC_INQUIRY /dev/rdsk/c20t0d1: I/O error
size: 104857600 Kbytes
diskinfo: can't SIOC_INQUIRY /dev/rdsk/c21t0d1: I/O error
total: 4.1943e+08

sir it brings me this report.

my officemate told me just to run vgdisplay -v vg01, compute for the total pe x alloc pe then less total used disk. but result still not accurate

Yes, vgdisplay will let you calcolate the free space - not sure your colleague's mathematics are quite right though. Maybe he meant "Free PE" x "PE Size (Mbytes)".

But of course that will not include any disks that are not added to vg01 (i.e. unallocated, or belonging to other volume groups, or managed by other volume management software such as Veritas Volume Manager). As I said before, you need to have a fairly intimate knowledge of the way your storage is configured to make these calculations.