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Calculating the Number of Rows and Average

 
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Top Forums UNIX for Dummies Questions & Answers Calculating the Number of Rows and Average
# 1  
Old 08-15-2008
Calculating the Number of Rows and Average
Hi All

I like to know how can we calculate the number of rows and the average of the values present in the file. I will not know what will be the rowcount, which will be dynamic in nature of the file.

eg.

29
33
48
30
28
# 2  
Old 08-15-2008
Code:
awk '{ sum+=$1
         rowcnt++}
       END {printf("average: %.2f  rowcount:%d", sum, rowcnt) }' inputfile

# 3  
Old 08-15-2008
This is untested code..

nawk 'NR==1{k=0;Sum=0}{print $1; k=k+1; Sum=Sum+$1}END{print "Raws=" k " AVG.= "Sum/k} inputfile
# 4  
Old 08-15-2008
Thanks...This works
awk 'NR==1{k=0;Sum=0}{print $1; k=k+1; Sum=Sum+$1}END{print "Raws=" k " AVG.= "Sum/k}' input File

But what iam looking for is
Output

<Name of the service> <AverageValue> <Number of Rows>
# 5  
Old 08-15-2008
could you provide us with example.... I dont really understand your request.. what do u mean by name of the service...
# 6  
Old 12-11-2008
Hi Jim, what does %.2f mean?
# 7  
Old 12-11-2008
Quote:
Originally Posted by grossgermany
Hi Jim, what does %.2f mean?
display two places after decimal point
 
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