UNIX for Dummies Questions & Answers

Hello,

I'm trying to grep for digits surrounded by non digits and I'm obviously misinformed. Could someone help me get this sorted out

here is what I have that is not working

grep -ho '\D([0-9]\{11\})\D' *.txt

Example for input and desired output needed, ty.

\D is a Perl regex extension and is not supported in grep in general.

Code:

grep -ho '[^0-9][0-9]\{11\}[^0-9]' *.txt

though that not quite what I'm looking for here are some examples

input examples:
some text I wrote +90123456789 and some more text
new line with different numbers 1234567890 notice only 10 digits
yet another line '11234567890'

output desired
+90123456789
1234567890
11234567890

also note that I do want the 10 digit number as well

thanks again

mcgrailm

grep -ho '[+0-9]\{10,12\}' some.txt

To really enforce the requirement that the matches have to be adjacent to non-number characters, you could egrep -o '[^0-9][0-9]+[^0-9]' | grep -o '[0-9]*' but given your usage scenario, I guess you didn't mean that the matches always have to be adjacent to non-number characters ... in which case just simply grepping for numbers like Ikon suggests will work excellently. (By definition, wildcards like \{10,12\} and * are greedy, so will match as many numbers as possible.)