UNIX for Dummies Questions & Answers

I am writing a very basic shell script, and I have never really written anything in UNIX before.

here is what I have:

#!/bin/ksh

set P = 045
set R = 001
for $R < $P
RPT = report005_${R}.lis
PDF = report005_${R}.pdf
/home/pcl2pdf $RPT $PDF
add 1 to $R
done

basically, I need to run this loop 44 times. Each time, it will set the report and PDF names, then run the command below (which converts the .lis file to a .pdf file). When complete, I need to increment the counter.

This script is not working, and without any documentation or knowledge of UNIX, I am stuck. Can someone assist with this script please?

Thank you in advance.

Mark

Here's an example to do a loop of 44 times:

Code:

for i in `seq 1 44`
do
  # do your stuff here
done

But if you're not familiar with scripting, you really should read some tutorials:

https://www.unix.com/answers-frequent...tutorials.html

Regards

on eproblem i see is you should not put spaces in variables. and no spaces around the = sign.

P=045
R=001

would allow you to call $P and $R

do the same for all the vars.

Thanks everyone for your help. I almost have this working

Here is my last issue.

I set the one variable, and add to it

suf=`expr $suf + 1`

I always need my variable to be 3 characters, and zero filled. I did search, and found a TYPESET -Z which will right justify the value, and 0 fill it, but I am not sure if this is what I am looking for.

any suggesstions?

Thanks

Code:

> s_value=12
> echo $s_value
12
> s_value_t=$(printf "%.3d" "$s_value")
> echo $s_value_t
012