UNIX for Dummies Questions & Answers

File1.txt

.......
.......
OMC LA
OMC LK
OMC LS
........
........

Above is the content of File1.txt, i want to get the Number of Occurence to order, lets say if OMC LA = 1, OMC LS=3, and OMC LK=2..

omc_ident="OMC LA" or "OMC LK" or "OMC LS"

omc_num=`grep '^OMC' File1.txt| grep -n '^OMC $omc_ident$' | awk -F: '{ print $1 }'`

IF omc_ident is "OMC LS", then the omc_num is 3....

but in return i get a null value, any1 can help me to find out how i can correct this script...

Lots of things here:
the second 'grep' is looking for "OMC OMC LS" - you've got OMC followed by $omc_ident, which is set to "OMC LA" or something similar. Unfortunately, you've enclosed this in single quotes so what it is actually looking for is "OMC $omc_ident$" - variables aren't expanded inside single quotes. Also, grep -n prints the line number and line for each match, not the number of occurrences, use "grep -c" for a count. Then, why awk?

Try:
omc_num=`grep -c "^${omc_ident}$" File1.txt`

For one-liners like this it's easier to build them up gradually then multiple errors don't disguise each other -then look at simplifying.
if you'd tried
grep '^OMC' File1.txt and looked at the output
then
grep '^OMC' File1.txt| grep -n '^OMC $omc_ident$' and seen no output
then you would have improved your chances of solving the problem.
And read the man pages!
cheers
Steve

Thanks for explanation but yet it didnt solve my problem steve.....
grep '^OMC' File1.txt| grep -n '^OMC $omc_ident$' is return null as ur comment..
Pls let me know if there is any possible solution for this....

Is this what you're after :

Code:

#  cat infile
OMC LA
OMC LK
OMC LS
OMC LA
OMC LK
OMC LA


#  sort infile | uniq -c | sort -n
   1 OMC LS
   2 OMC LK
   3 OMC LA

HTH,

The problem is solved...


omc_num=`grep '^OMC' File1.txt| grep -n "^OMC $omc_ident$" | awk -F: '{ print $1 }'`