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# 1  
Old 06-03-2008
string manipulation


I have a file with rows of text like so :


I need to grab just the last digits(bolded) of each line without the proceeding text/numbers.

# 2  
Old 06-03-2008
echo 'E100005568374098100000015667' | sed 's/.*\(.....\)/\1/'

# 3  
Old 06-03-2008
To grab a value in a record without field seperators you have to know the positions of each field IMHO.
You can arbitrary begin at one of the position with a zero but you're never shure you have the right value.

# 4  
Old 06-03-2008
actually now that I think about it - I don't know what's common among the values you return.
Is it preceeded with more than one '0'?
echo 'E100005568374098100000056607' | sed 's/.*00\(.*\)/\1/'

# 5  
Old 06-03-2008
You always cut the last 5 characters, no matter if he needs 4 or 6 like in the other rows.

Yep, that's true. You have to know the possibilties of your file-to-be-parsed very well to limit the chances of unwanted behaviour.

So for the input presented we can say that when at least 5 zeros are in a row, that we can use them to separate the last digits we want:
sed 's/.*00000\([^0]*\)/\1/'

This will at least make sure, that even if you have 1 up to 4 zero in your last digits, the will be separated ie. parsed correctly. If you have at the end a "600000", you have a problem again. For this I don't have a good solution, as I just thought, that there at least a number of zeros following each other before the last digits come, you want.
If you know that the last digits are always not more than 6 digits, you can parse them like vgersh99 did, ie. add a dot or write it another way and after that cut off all leading zeros.

EDIT: @vgersh99
Oh you saw it already while I was writing Smilie
# 6  
Old 06-03-2008
Thanks everybody, learnt a lot from this. The last piece of code posted has done the trick.
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