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pipe output to script as command line argument

 
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# 1  
Old 04-26-2008
pipe output to script as command line argument
i want to redirect output of one command as the command line argument of another script

for example, say i would run this command:

Code:
 
find . -xdev -type f -size +4096 -exec ls -al {} \;

i wan to be able to do something like:

Code:
echo +4096 | find . -xdev -type f -size ****** -exec ls -al {} \;

Is this possible in ksh?
# 2  
Old 04-26-2008
Code:
find . -xdev -type f -size `echo +4096` -exec ls -al {} \;

Depending on where the +4096 is meant to come from, you might be looking for something as simple as

Code:
#!/bin/sh

case $# in 1);; *) echo "Syntax: $0 size -- find files of size <size>" >&2; exit 1;; esac

find . -xdev -type f -size "$1" -exec ls -al {} \;

Another construct which is useful sometimes is

Code:
sed -e 's/.*/find . -xdev -type f -size & -exec ls -al {} \;/' fileofsizeswewanttofind |
sh

And finally, you might want to look at xargs, which allows for rather similar constructions; but it's tricky for this particular case.
# 3  
Old 04-26-2008
actually i was not looking to write a script.

i wanted a simple way to do this via the command line. and my find was jut an example. i wanted something that would work for any script/command i am running.

make sense or did i just confuse people?
# 4  
Old 04-26-2008
And the backticks don't fit that definition?

Anything you can do in a script, you can do on the command line, anyway.

For the general solution, xargs is probably closest to what you have in mind, but it doesn't interact nicely with find -exec, because they both want the {} for themselves. (Actually, you can in fact specify an alternate placeholder for xargs.)

Code:
echo fnord | xargs ls -l

would be the xargs way of saying "ls -l fnord", and

Code:
echo +4096 | xargs -i find . -xdev -type f -size {} -ls

would be something similar for find, albeit without the -exec.
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