UNIX for Dummies Questions & Answers

I have a file driven menu using the select feature in ksh. I like doing it this way, however I would prefer running a bash. Is there some eqivalent way of doing this in a bash shell?


ie

select file in *.ascii 
do
typeset -u REPLY
if [ $REPLY = "Q" ] ; then
break
fi
    if [ ! -f ${file}.type ] ; then
        perl $ENVIRON/$CLIENT/code/addtype.pl $file ${file}.type
        if [ ! -f ${file}.type ] ; then
            print "\nProgram E rror!\n"
            break 
        fi
    fi
    type=${file}.type
    process
    break
done


Guidance and/or ideas are much appreciated.

According to the man page on bash it uses select also.

User Commands BASH(1)

select name [ in word ] ; do list ; done
The list of words following in is expanded, generating
a list of items. The set of expanded words is printed
on the standard error, each preceded by a number. If
the in word is omitted, the positional parameters are
printed (see PARAMETERS below). The PS3 prompt is then
displayed and a line read from the standard input. If
the line consists of a number corresponding to one of
the displayed words, then the value of name is set to
that word. If the line is empty, the words and prompt
are displayed again. If EOF is read, the command com-
pletes. Any other value read causes name to be set to
null. The line read is saved in the variable REPLY.
The list is executed after each selection until a break
or return command is executed. The exit status of
select is the exit status of the last command executed
in list, or zero if no commands were executed.