UNIX for Dummies Questions & Answers

not sure if i should post here or "shell programming"

anyway, i am just start learning perl.

1 #!/usr/local/bin/perl
2
3 $test1="Iam";
4 if ($test1=="anything")
5 {
6 print "show me\n";
7 }
when i run the program, it display "show me" all the time regardless the if condition. what is going on here? can any help me?

thks

Gusla

Hi,

you may only use the operator "==" for numerical matches. In this case, use "eq" instead, as you are trying to match strings.

Example:

Code:

#!/usr/local/bin/perl

$test1="Iam";

if ($test1 eq "anything") {
        print "show me\n";
} else {
        print "Not matching.\n";
}

This prints "Not matching."

HTH,
Lexx

added code tags for readability --oombera

thks Lexx, u r coool

You're welcome

Anyway, if you just started learning Perl, you might find this book interesting: http://www.oreilly.com/catalog/lperl3/

HTH,
Lexx

--
:wq!