UNIX for Dummies Questions & Answers

I'm looking a Grep or egrep statement that would allow me to exclude the a range of ip address via the last octet
example egrep -v "*.*.*.(54|61)" from a syslog file.... would this work?

and ip address is something like 255.255.255.255. and you what an RE for that ?

[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+ you may like to fine tune it a bit

Maybe something like:

Code:

egrep -v "[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[^54-61]" file

Not positive if that last part of the regexp works...

I have a similar question, so I'll post it here.

I have a script that blocks IPs, but checks first to see if the given IP exists in a file before proceeding. In one case, it's /etc/mail/access (Sendmail). The format is generally:

11.22.33 REJECT or SOME MESSAGE

Now, say I log an IP of 11.22.3, when I egrep for it, it will also match 11.22.33, which I don't want.

So I'm trying to figure out how to limit the egrep search for only that IP - establishing a boundary on the search, which I'm not able to figure out.


thanks.

Put a space after the last number?

Code:

egrep "11.22.3 " file

That doesn't work, as the next character is a TAB --

I'm still puzzled why the metacharacters \< and \> don't work for bounaries, too.

Thanks.

grep "11.22.3\>" file will work, you may have left out the quotes