UNIX for Dummies Questions & Answers

Hi
I'm hoping I could get some help on the following. I'm writing a script which will in turn create an ftp script then excecute it. eg

echo "user $user $pass" > $script
echo "cd $remote_dir" >> $script
echo "bi" >> $script
echo "mput $file" >> $script
echo "bye" >> $script
ftp -n -i $ip < $script

I am having problems trapping errors if $remote_dir does not exist.

I've tried the following:

echo "cd $remote_dir" >> $script
echo "bi" >> $script
echo "mput $file" >> $script
echo "bye" >> $script
ftp -n -i $ip <$script
if [ $? -ne 0 ] then .......

This doesn't work because ftp always returns '0' even if $remote_ dir does not exist.

echo "cd $remote_dir" >> $script
echo "bi" >> $script
echo "mput $file" >> $script
echo "bye" >> $script
ftp -n -i $ip <$script 2>$error_file

Here an 'empty' error file is created on the remote server and error messages still display to screen.

How can I test for errors or how can I create an error file on the local server? Any help would be greatly appreciated!

Thanks

There is no really great way to do this. ftp send s back as many messages as it wants. It's not like you can count them or anything. When you run ftp manually, you get an ftp prompt when the messages have finished arriving. But there is no way to that non-interactively. My compromise is to wait a few seconds and then inspect the last message to arrive. This is not perfect, but as a practical matter, I can get it to work. Here is some sample code...

Code:

#! /usr/bin/ksh

print -n password -
stty -echo
read PASSWD
stty echo

SYSTEM=ftp
USER=user1
OUTPUT=/tmp/x-ftp$$

ftp -nv >$OUTPUT 2>&1 |&
print -p open $SYSTEM
print -p user $USER $PASSWD
print -p cd tmpooo
sleep 5
tail -1 $OUTPUT | read code junk
if [[ $code = 550 ]] ; then
        echo error on cd
else
        echo cd worked tranferring file...
        print -p binary
        print -p put file

fi

print -p bye
wait
rm $OUTPUT
exit 0