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Date Conversion

 
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# 1  
Old 01-29-2008
Date Conversion
I need to change the date in a text file from dd/mm/yyyy to dd-mmm-yyyy.

Any help would be much appreciated.

Thanks
# 2  
Old 01-29-2008
use:

Code:
sed 's_\(..\)/\(..\)/\(....\)_\1-\2-\3_g'

e.g.
Code:
#   date '+%m/%d/%Y'
01/29/2008
# date '+%m/%d/%Y' | sed 's_\(..\)/\(..\)/\(....\)_\1-\2-\3_g'
01-29-2008

# 3  
Old 01-29-2008
echo '23/12/2004'|sed -e 's/\([0-9][0-9]\)\/\([0-9][0-9]\)\/\([0-9][0-9][0-9][0-9]\)/\1-\2-\3/g'
# 4  
Old 01-29-2008
Quote:
Originally Posted by MJDRM
I need to change the date in a text file from dd/mm/yyyy to dd-mmm-yyyy.

Any help would be much appreciated.

Thanks
Correct me if I'm wrong, but I think he is wanted the month to be the 3 letter month, such as Jan, Feb, Mar, etc (dd-mmm-yyyy.)

I'm having some trouble figuring how to find the date in the file and then split it to match on the mm, but once that piece is in the puzzle he could do
Code:
case $mm in
01) Jan;;
02) Feb;;
etc...

# 5  
Old 01-29-2008
Convert today's date to dd-mmm-yyyy
code:
> dtx=$(date '+%d-%b-%Y')
> echo $dtx
29-Jan-2008
>
# 6  
Old 01-29-2008
To get to that midlle field... and start a case statement...
Use today as an example to have a date in the format of the question
Store to mm the 2nd part (month) of the date
You could then do a case on $mm

> idtx=$(date '+%d/%m/%Y')
> echo $idtx
29/01/2008
> mm=$(echo $idtx | cut -d"/" -f2)
> echo $mm
01
>
 
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