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# 1  
Old 01-11-2008
Shell Sript

Hi All,

I have four different files in four different directories.
Each file contains exactly the same format
logincode Forename Surname TutGroup Mark

Basically i want to grab all the marks from each file and put them onto the end of one login code by using a shell script. I can grab all the marks just by
cut -f 5 -d ' ' file1 file2 file3 file3

But then i want to add it on the end of the correct login code so i would have
logincode mark1 mark2 mark3 mark4

I have tried using join but can only do this for 2 files (i have 4) and it doesn't work if there is more than one record? i have tried
join -v 2 file1 file2 but this only displays record two.

Hope that makes sense
# 2  
Old 01-11-2008
 awk '{c[$1]=c[$1]" "$5 }END{for (i in c){print i,c[i]}}' file1 file2 file3 file4

# 3  
Old 01-11-2008
Your an absolute genius! It works perfectly!!!!
I don't really understand it all fully though. Could you explain?
Also if you wanted to do it without loops how could this be done?
I know how to use awk to calculate an average number for the whole file but how could i do this for one line? For example
50 60 70 (average mark here)
40 30 20 (average mark here)

Originally Posted by Tytalus
 awk '{c[$1]=c[$1]" "$5 }END{for (i in c){print i,c[i]}}' file1 file2 file3 file4

Last edited by jazz8146; 01-11-2008 at 02:02 PM..
# 4  
Old 01-11-2008
it creates an array for each firstfied, and adds on every 5th field where the firstfield atches... (the " " is the concatenation operator)

hmm - maybe not the clearest...hope the following makes more sense:

create array of values based on first col with concat 5th col values:
{c[$1]=c[$1]" "$5 }

Then loop through array and print out values:
{for (i in c){print i,c[i]}}'

for the average you could do:

 awk '{c[$1]=c[$1]" "$5 }END{for (i in c){print i,c[i]}}' file1 file2 file3 file4 | awk '{t=0;for (i = 2; i<=NF; i++) t+=$i;print $0,t/(NF - 1)}'

(i.e loop over 2nd through end cols, add 'em up and spit out the orig file with the avg tagged on...)

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