UNIX for Dummies Questions & Answers

All,


Please find the below comand . I am trying to list the file that has not been accesed is past 14 days . But when you look at the display the directory "crecv1" which has date as today is displayed .. Why it is happening .

I send this code instead of ls -ltr as rm -f -r in production . I mean it to remove the file that was not accesed in 14 days . Instead it removed all the filed from crecv1 directory .. Please let me know why .. I am wried up ..


find /work/can/transfer/ -name "*" -mtime +14 -exec ls -ltr "{}" ";"


total 144512
drwxr-xr-x 2 crcv1ftp canusr 8192 May 1 2007 crcv1ftp
-rwxrwxrwx 1 scottj canusr 72928579 May 1 2007 spcurruswst.gz
-rwxrwxrwx 1 scottj canusr 1006258 Sep 19 15:33 s7041012_copy
drwxrwxrwx 2 hamelmi1 canusr 8192 Nov 6 09:28 item
drwxrwxrwx 3 crcv1ftp canusr 24576 Jan 7 12:15 crecv1
-rwxrwxrwx 1 scottj canusr 1006258 Sep 19 15:33 /work/can/transfer/s7041012_copy
-rwxrwxrwx 1 scottj canusr 72928579 May 1 2007 /work/can/transfer/spcurruswst.gz
/work/can/transfer/crecv1/.ssh unreadable
total 0
find: cannot open /work/can/transfer/crecv1/.ssh
total 0
-rw-r--r-- 1 crcv1ftp canusr 0 Sep 4 2003 *
-rw-r--r-- 1 crcv1ftp canusr 0 Sep 4 2003 /work/can/transfer/crcv1ftp/*
-r--r--r-- 1 crcv1ftp canusr 832 Nov 14 2000 /work/can/transfer/crcv1ftp/.cshrc
-r--r--r-- 1 crcv1ftp canusr 347 Nov 14 2000 /work/can/transfer/crcv1ftp/.exrc
-r--r--r-- 1 crcv1ftp canusr 334 Nov 14 2000 /work/can/transfer/crcv1ftp/.login
-r--r--r-- 1 crcv1ftp canusr 439 Nov 14 2000 /work/can/transfer/crcv1ftp/.profile
-rw------- 1 crcv1ftp canusr 2962 May 1 2007 /work/can/transfer/crcv1ftp/.sh_history
total 0


Thanks,
Arun

Your command is looking for anything, file OR folder since you aren't specifying it to look ONLY for files with "-type f".

Try this instead:

Code:

find /work/can/transfer/ -type f -mtime +14 -exec ls -ltr "{}" ";"

I hope this helps....Cassj

****** I had to come back and update this after looking at it further. *********
I just noticed this too. You said wanted to find files that had "not been accessed is past 14 days". You should use "-atime" (accessed) instead of "-mtime (modified). And since you wanted the ones that were NOT accessed, you should use "-not -atime -14". "-14" means 14 days or less. So to put it all together:

Code:

find /work/can/transfer/ -type f -not -atime -14 -exec ls -ltr "{}" ";"

Hmmm, this seems to select the right files when I do it:

Code:

# find /tmp/ -name "*" -mtime +14 -exec ls -ldtr {} ; | wc -l
     120

# find /tmp/ -name "*" -mtime -14 -exec ls -ldtr {} ; | wc -l
      28

# find /tmp/ -name "*" -exec ls -ldtr {} ; | wc -l
     148

You might want to add "-type f" to limit the search to files only.

First "-atime +14" selects files whose last access was more than 14 days ago. See https://www.unix.com/tips-tutorials/2...ime-atime.html


Next consider a set of files like this:
/toplevel
/toplevel/dir1
/toplevel/dir1/file1
/toplevel/dir1/file2

When you put files in dir1, this modifies dir1 but not toplevel so a
find /toplevel -mtime +14
will eventually find /toplevel. So then you do a "rm -rf /toplevel" the entire directory hierarchy is removed. "ls -ltr /toplevel" will report on the entire hierarchy as well. The find command is already scanning the directory structure. You don't want to use -r on the commands spawned from it in most cases. Even without -r, ls will, by default, show the contents of a directory unless you use -d with it.

Actually the command i issued is

find /work/can/transfer/ -name "*" -mtime +28 -exec rm -f -r "{}" ";"

But what hapenned was in side the /work/can/transfer/ there is a directory called /crecv1.

When the script run on first day from cron it changes the time of the directory /crecv1 to the current day even though it dodnt delete any file from the directory /crecv1.

And when the script run on second day . What it is doing was it is deleting all files from the directory even though the rule was to delete 28 days mtime.

Please help me to know why it happens .

THanks,
Arun