UNIX for Dummies Questions & Answers

Hi,

I want to setup a cronjob that will delete logs every 2 hours. I have script that delete logs per day. but logging is too big and i want to run a conjob that will delete every 2 hours.

this is my current command but it deletes on a per day basis.

find . -name "*.log[0-9]*" -o -name "*.log" -mtime +3 |xargs rm -fR {} \;

One way of doing it would be to set up a cron job that calls a shell script every hour.

Within the shell script, use the date utility to return the hour_of_the_day in 24 hr format. Test if (hour_of_the_day % 2) is zero. If so execute the remainder of the script, otherwise exit.

Seems like you be better off managing your logfiles by rolling over (or archiving) them.
If your logfiles are generated on mount /u01/logfiles (for example). You may want to consider moving them to /u09/arch/logfiles and consider compressing them after the move. Then perform the remove/delete on those compressed files on the second mount.

That ensures that you have a current copy available and an archive copy .

Just a thought.
Avoids you being caught out if you need the current logfiles and the delete step rolls around.

Cheers,
Cameron

Otherwise you can use your existing find ....

01 0,2,4,6,8,10,12,14,16,18,20,22 find [requires a starting point] -name "*.log[0-9]*" -o -name "*.log" -mtime +3 |xargs rm -fR {} \; >> /var/adm/opslogs/dlt_logfiles.log

Hope that helps some.

Cheers,