Question about SED for excluding lines

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# 1  
Old 11-20-2007
Question about SED for excluding lines


I'm using the SED instruction for substitution in a shell script. I'd like to improve it a bit. The instruction looks like this right now:

sed '/PRAGMA/!s/package/apps.package/g' $fich_src

I'm replacing the word "package" by "apps.package" for all the lines of the file $fich_src EXCEPT the ones that contain the word PRAGMA.
This works fine, but I want to add one more word for the lines exclusion. In other words, I want the substitution to take place for all the lines except the ones that contain the word PRAGMA or the word END (either or these two words)
I couldn't figure out the syntax. I've tried with two -e strings, I've tried to pipe, but it didn't work. What is the syntax to achieve what I want?

Thank you
# 2  
Old 11-21-2007
Some versions of sed, including GNU sed, will support what you want to do

sed '/\(PRAGMA\|END\)/!s/package/apps.package/g' $fich_src
# 3  
Old 11-21-2007
Hi fpmurphy,

I tried your suggestion but it didn't work, the substitution occured for the lines containing either of these words.

Thanks anyway
# 4  
Old 11-21-2007

The sed solution of fpmurphy worked for me with GNU sed version 4.1.2.

What is the version of sed that you are using?

Are you required to use sed for some reason? ... cheers, drl
# 5  
Old 11-22-2007

I need to compile Oracle packages for a certain list of schemas. It needs to be done automatically, so doing it through a shell is the most convenient way for our DBA.
I won't provide as many packages files as there are schemas, it would be long and not really professional. Moreover there are many references to other packages within each package, and each of these references needs to be prefixed with the schema.
So the best I thought is to have a file which contains the list of the schemas, and loop through that file to compile the package files, using SED to prefix each package reference with the schema's name.

How do I find out which version of sed I'm using, and if gnu sed is available?

# 6  
Old 11-22-2007
Originally Posted by greg
How do I find out which version of sed I'm using, and if gnu sed is available?
Like so:
% sed --version
GNU sed version 4.1.2
Copyright (C) 2003 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
to the extent permitted by law.

or man sed ... cheers, drl
# 7  
Old 11-22-2007

Here's a fairly vanilla awk script:
#!/usr/bin/env sh

# @(#) a1       Demonstrate feature.

set -o nounset

## Use local command version for the commands in this demonstration.

echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version bash awk


echo " Input file:"
cat $FILE

echo " Results:"
awk '
/PRAGMA|END/    { print ; next }
                { gsub("package","apps.package")

exit 0

% ./a1

(Versions displayed with local utility "version")
GNU bash 2.05b.0
GNU Awk 3.1.4

 Input file:
one package
two another package
thr package with PRAGMA (should not prepend apps.)
fou addition package at END (should not prepend apps.)
fiv yet another package
six last package

one apps.package
two another apps.package
thr package with PRAGMA (should not prepend apps.)
fou addition package at END (should not prepend apps.)
fiv yet another apps.package
six last apps.package

Best wishes ... cheers, drl
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