UNIX for Dummies Questions & Answers

#!/bin/sh -

# @(#) s2       Demonstrate extraction of date of first Monday of
# month and year from display of "cal" utility..

# Usage: s2 [month -> this month] [year -> this year]

debug=":"
debug="echo"

CAL=/usr/bin/cal

todaymonth=$( date +%m )
todayyear=$( date +%Y )
MON=${1-$todaymonth}
YEA=${2-$todayyear}

$CAL $MON $YEA |
awk '
NR == 1 { next }
NR == 2 { next }
NF <= 5 { next }
NF == 6 { print $1 ; exit }
NF == 7 { print $2 ; exit }
'

exit 0

% ./s2
3

% ./s2 10 2008
6

cal | sed '1d' | cut -d" " -f 2 | head -3 | sed '/^$/ d' | grep -iv mon

cal | sed '1d' | cut -d" " -f 2 | head -3 | sed '/^$/ d' | grep -iv mon

Mo
2

   September 2007
Su Mo Tu We Th Fr Sa
                   1
 2  3  4  5  6  7  8
 9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30

number=$(date +"%u%d")
if [ $number -le 107 ] ;then
.....
fi

$CAL $MON $YEA |

/usr/bin/cal 09 2007