renaming files


 
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# 1  
renaming files

Hello all-

I need to rename files by adding an embedded 0
e.g.
aaa_bbb_1234 needs to become aaa_bbb_01234

The aaa and 1234 will change but the bbb_ can be my anchor.

TIA
# 2  
ok so I made this _way_ to complicated....

I first tried ( with no luck on lots of permutations ):
for i in `ls *bbb_*`
do
a=`echo $i | sed -e 's/\(*bbb_\)\(*\)/\10\2/g'`
mv $i $a
done

The zero was problematic also the replay of \1 and \2 did not seem to work at all.

Then after playing with it I realized I was just making it too fancy. Knowing that I had an anchor made it simpler:

for i in `ls *bbb_*`
do
a=`echo $i | sed -e 's/bbb_/bbb_0/g'`
mv $i $a
done
# 3  
i tried this option--

cat file1
aaa_bbb_1234
ccc_bbb_2315
ddd_bbb_9856

sed 's/???_bbb_1234/???_bbb_0{????}/g' file1
sed 's/???_bbb_????/'\(???_bbb_0????\)'/g' file1
sed 's/???_bbb_???/???_bbb_0\(????\)/g' file1

but this option is not working still shwoing the same output.
Can anyon eexplain me why?

Thanks
Namish
# 4  
First move all the files with similar names to another file:


find . -name "*_bbb_*" > names.txt

Then use the sed command



sed 's/\(.*\)_\(.*\)_\(.*\)/\1_\2_0\3/g' names.txt
# 5  
Quote:
Originally Posted by ohagar
[...]
aaa_bbb_1234 needs to become aaa_bbb_01234
[...]
Depending on your shell you could:

Code:
zsh 4.3.4% touch aaa_bbb_1234 bbb_bbb_5678
zsh 4.3.4% autoload -U zmv
zsh 4.3.4% zmv -n '(*)' '${f/_bbb_/_bbb_0}'
mv -- aaa_bbb_1234 aaa_bbb_01234
mv -- bbb_bbb_5678 bbb_bbb_05678
zsh 4.3.4% # remove "-n" to execute
zsh 4.3.4% bash
bash 3.2.13(1)$ for f in *_bbb_*;do
> echo "mv $f ${f/_bbb_/_bbb_0}"
> done
mv aaa_bbb_1234 aaa_bbb_01234
mv bbb_bbb_5678 bbb_bbb_05678
bash 3.2.13(1)$ # remove the echo command to execute
bash 3.2.13(1)$ sh
$ for f in *_bbb_*;do
> echo "mv $f ${f%_bbb_*}_bbb_0${f#*_bbb_}"
> done
mv aaa_bbb_1234 aaa_bbb_01234
mv bbb_bbb_5678 bbb_bbb_05678
$ # remove the echo command to execute

# 6  
Code:
[/tmp]$ cat txt
aaa_bbb_1234
bbb_bbb_1345
ccc_bbb_1456
[/tmp]$ cat test.ksh
#! /bin/ksh
#
#

while read file
do
    post=${file##*bbb_}
    pre=${file%%$post}
    echo "old file=[$file]"
    echo "new file=[${pre}0${post}]"
    # mv "${file}" "${pre}0${post}"
done < txt
[/tmp]$ ./test.ksh 
old file=[aaa_bbb_1234]
new file=[aaa_bbb_01234]
old file=[bbb_bbb_1345]
new file=[bbb_bbb_01345]
old file=[ccc_bbb_1456]
new file=[ccc_bbb_01456]
[/tmp]$

# 7  
Quote:
Originally Posted by namishtiwari
i tried this option--

cat file1
aaa_bbb_1234
ccc_bbb_2315
ddd_bbb_9856

sed 's/???_bbb_1234/???_bbb_0{????}/g' file1
sed 's/???_bbb_????/'\(???_bbb_0????\)'/g' file1
sed 's/???_bbb_???/???_bbb_0\(????\)/g' file1

but this option is not working still shwoing the same output.
Can anyon eexplain me why?

Thanks
Namish
Sed actually tries to match the question marks you provided in the regex. Instead of the question mark you should use a . (dot) to match any character. Also in the sed world, a question mark '\?' is used to match zero or one occurrence of the preceding character. From info sed

Code:
`\?'
     As `*', but only matches zero or one.  It is a GNU extension.

Examples:
`a\?b'
     Matches `b' or `ab'.

Using a . would translate to either of

Code:
sed -e "s/\(...\)_bbb_1234/\1_bbb_01234/g" file1
sed -e "s/\(...\)_bbb_\(....\)/\1_bbb_0\2/g" file1

 

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