Passing DISPLAY variable through rsh


 
Thread Tools Search this Thread
Top Forums UNIX for Dummies Questions & Answers Passing DISPLAY variable through rsh
# 1  
Old 02-16-2001
I am trying to add a menu item (Openwin menu) to do an rsh and execute a script which open a graphical tool. The problem I am having is that I cannot seem to pass the display variable. The OS for both boxes is Solaris 2.6.
Thanks,
Chuck
# 2  
Old 02-16-2001
Many X applications will take a "-display" argument. Something like:

xv -display sunbox:0


Another alternative is to use ssh, as it handles the display variable automatically.
# 3  
Old 02-16-2001
Unfortunately the application is a vendor provided program which does not support a "-display" flag. Their answer is to set the display from the prompt, but most of our users aren't UNIX literate and I would prefer not to drop them on the shell.
# 4  
Old 02-16-2001
Then how about:

#!/bin/sh
xhost +otherhost
rsh otherhost "export DISPLAY=host:0 ; /path/to/app"
# 5  
Old 02-16-2001
Finally

Thank you for your help. I finally got it to work. What I did was exec this on the local box from the Openwin menu;

rsh hostname /path/to/script/eventmonitor.sh $DISPLAY

Then eventmonitor.sh on the remote box looks like;

#!/bin/sh
PATH=/blah:/more/blah:/path/to
export PATH
DISPLAY=$1
export DISPLAY
exec /path/to/eventmonitor

I can't beleive it took me all day to figure this out!
 
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies

2. Shell Programming and Scripting

Passing dynamic variable within another variable.

I have a small program which needs to pass variable dynamically to form the name of a second variable whose value wil be passed on to a third variable. ***************** Program Start ****************** LOC1=/loc1 PAT1IN=/loc2 PAT2IN=/loc3 if ; then for fpattern in `cat... (5 Replies)
Discussion started by: Cyril Jos
5 Replies

3. Shell Programming and Scripting

Cannot pass rsh and awk command into a variable

Hello, I'm having some issues getting a home dir from a remote server passed to a variable. Here is what I have so far: rsh server "(ls -ld /home*/user | awk '{print \$9}')" /home3/userThat works fine and brings back what I need. But when I try to add it to a variable it goes all... (3 Replies)
Discussion started by: elcounto
3 Replies

4. Shell Programming and Scripting

Passing variable with *

Hi Folks, I would like to pass a variable with a wild card in an argument. My script works if I don't use a wildcard but fails when I use *. I want to use the script like: scriptname -F <filename*> @ i = 0 while ($i <= ${#argv}) switch ($argv) case -F: set j = `echo $i +1... (2 Replies)
Discussion started by: dixits
2 Replies

5. Shell Programming and Scripting

awk, double variable, for loop and rsh

Hello folks, I've a (perhaps) simple question. In a text file I've : server_name1: directory1 server_name2: directory2 server_name3: directory3 I want to make a loop that lets me connect and operate on every server: rsh server_name1 "ls -l directory1" I've tried with awk,... (6 Replies)
Discussion started by: gogol_bordello
6 Replies

6. UNIX for Dummies Questions & Answers

Passing a command in a variable

I need to set up a strange system through which an arbitrary command is sent to a number of different servers (well, actually, VPS accounts). We have a command "vpass" that "passes" a command from the root level to resident VPS accounts. Suppose I wanted each VPS to do some trivial thing, like... (3 Replies)
Discussion started by: treesloth
3 Replies

7. Shell Programming and Scripting

Passing shell variables to a rsh command

I noticed my script is not passing the value of variable alert to the rsh command. I need some assistance, please. This is a solaris environement. Thanks! :confused: #!/bin/sh echo -n "Alert number:" read alert rsh rhost_name 'egrep $alert /opt/var/log/*.logs' (2 Replies)
Discussion started by: lopus
2 Replies

8. Shell Programming and Scripting

passing a variable inside another variable.

Any help would be great. I know this is a dumb way of doing this, but I would like to know if there is a solution doing it this way. I'm very new at this and I'd like to learn more. Thanks! :D:D count=0 while ; do echo "enter your name" read name_$count let count=count+1 done ... (2 Replies)
Discussion started by: reconflux
2 Replies

9. UNIX for Dummies Questions & Answers

passing a variable inside a variable to a function

I would like to know how to pass a variable inside a variable to a function. sample code below -------------- for x in 1 9 do check_null $C$x ##call function to check if the value is null if then echo "line number:$var_cnt,... (2 Replies)
Discussion started by: KingVikram
2 Replies

10. UNIX for Dummies Questions & Answers

Variable passing

Hi, If a script A(Parent) is running and script B(child) is run from script A, will the variables in script A be past to script B? Will the variables exist only for the duration of running the script? Thank you (2 Replies)
Discussion started by: whugo
2 Replies
Login or Register to Ask a Question