UNIX for Dummies Questions & Answers

I need to check the number of input parameters in the K shell script.
Also, I want to exit if the no of parameters is not met.


How can I do that ?

Thanks
LS1429

I think I see what you mean... For example, the command:
myscript.ksh -a 1 -q
has 3 input parameters... Am I correct? If so, you can use $# to count them. Here is an example:

Code:

#!/usr/bin/ksh
 if [ "$#" = "0" ]; then
     echo "You don't have any arguments! "; exit
fi
echo $#

To try this script, try this:
chmod +x scriptname
./scriptname
./scriptname 1 b 3 d
See what happens.

If you have any more questions, please feel free to post back. I hope I got what you were asking.

Yeah thatz it.
One more thing. But I am not clear why the ; after condition is really needed or not

if [ $# -ne 1 ]
then
echo "Provide one Parameter "
exit 1
fi

Thanks
LS1429

Take an easier example, the date and who commands. If we want to run both commands, we might use two lines:
date
who
or we can enter both commands on a single line if we use the semicolon like this:
date ; who
But we gotta have something separating the two commands. Usually we have the newline character as the delimiter between commands, but the semicolon also works.

So it's a matter of style whether you use
if [ ... ] ; then
or
if [ ... ]
then

I like the first style because it lets more of the script be visible on a page. But I wouldn't call the second style "wrong".