UNIX for Dummies Questions & Answers

Hello all,

I'd like to remove files which is returned by the following statement

ls -l arch*.dbf|grep "`date|cut -c5-10`" (cut -c5-10 =Mar 20)

To achive this,I tried the following statments but none worked ..

rm < `ls -l arch*.dbf|grep "`date|cut -c5-10`"`

rm `ls -l arch*.dbf|grep "`date|cut -c5-10`"`

ls -l arch*.dbf|grep "`date|cut -c5-10`" -exec rm -f {} \;


Any ideas ?

Thanks for your time ..

Try this:
ls -l arch*.dbf|grep "`date|cut -c5-10`"| xargs rm

you can do a loop
eg

Code:

for file in `ls .......|grep ....`
do
   rm $file
done

except where the filenames contain spaces in either case.

Perderabo
Thanks for the quick reply ..I tried your suggestion but got the following error ..

oracle@westpark>ls -l

total 6
-rw-r--r-- 1 oracle dba 6 Mar 21 00:12 arch1.dbf
-rw-r--r-- 1 oracle dba 5 Mar 21 00:12 arch2.dbf
-rw-r--r-- 1 oracle dba 7 Mar 21 00:12 arch3.dbf

oracle@westpark>ls -l arch*.dbf|grep "`date|cut -c5-10`"|xargs rm

rm: illegal option -- w
rm: illegal option -- -
rm: illegal option -- -
rm: illegal option -- -
rm: illegal option -- -
rm: illegal option -- -
usage: rm [-fiRr] file ...

oracle@westpark>ls -l

total 6
-rw-r--r-- 1 oracle dba 6 Mar 21 00:12 arch1.dbf
-rw-r--r-- 1 oracle dba 5 Mar 21 00:12 arch2.dbf
-rw-r--r-- 1 oracle dba 7 Mar 21 00:12 arch3.dbf


ghostdog74

Thanks for the quick response .I know your suggestion will work ,but I'm trying to achive this using a single statement ..

Thanks

Then try this:
ls -l arch*.dbf|grep "`date|cut -c5-10`"| awk '{print $NF}' | xargs rm

combining it,

Code:

ls -l  | awk -v var="`date | cut -c5-10`" '{ if( match($0, var) ) { print $NF } }' | xargs rm