counter / increment problem within echo stmt


 
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# 1  
Old 02-07-2001
Question

Simple script trying to increment a counter within an echo statement never gets past 1 - PLEASE HELP!

Thanks.
~~~~~~~~~~~

#!/bin/sh
stepup()
{
STEP=`expr $STEP + 1`
echo $STEP
}

#
# Initialize variables
#
STEP=0

echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
echo "Counter Value: `stepup`"
# 2  
Old 02-07-2001
the problem is that your function "stepup" gets evaluated at the beginning of execution. I would do something like this instead:


#!/bin/sh

stepup()
{
let STEP=$1+1
echo $STEP
}

STEP=0

STEP=`stepup $STEP`
echo "Counter: $STEP"
STEP=`stepup $STEP`
echo "Counter: $STEP"
STEP=`stepup $STEP`
echo "Counter: $STEP"
STEP=`stepup $STEP`
# 3  
Old 02-08-2001
Network

Is there any way to evaluate the function "stepup" and echo/print it out in one statement or are we stuck doing 2 separate statements - one to evaluate the function and another to display it. Is there a way to do it within the function (ie, return)?

Thanks.
 
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