grep/cat/more -- search in a txt file and display content from a specific "keyword"


 
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# 1  
grep/cat/more -- search in a txt file and display content from a specific "keyword"

Hi,

I have a .txt file

Sample:

Code:
=====================
NEXT HOST
=====================
 AEADBAS001
ip access-list extended BLA_Incoming_Filter
ip access-list extended BLA_Outgoing_Filter
access-list 1 permit xxxxxxxxxxxxxx
access-list 2 permit xxxxxxxxxxxxxx
=====================
NEXT HOST
=====================
 AEADBMP002
access-list 1 permit xxxxxxxxxxxxxx
access-list 2 permit xxxxxxxxxxxxxx
access-list 22 permit xxxxxxxxxxxxxx
=====================
NEXT HOST
=====================
 AEADBMP003
ip access-list extended GAA_Incoming_Filter
ip access-list extended GAA_GW_Outgoing_Filter
access-list 1 permit xxxxxxxxxxxxxx
access-list 2 permit xxxxxxxxxxxxxx

I want to do a more/grep or cat and start the output from this line "AEADBMP002"...

So all the above information is not showed but starting from that point where it findes the string "AEADBMP002" the output is shown.

How do I do that?

Thanks,
# 2  
something like this,

Code:
awk '/AEADBMP002/, /\$/ {print}' file

# 3  
Code:
sed -n "/AEADBMP002/,$ p" file

# 4  
How do I do this per page?

The file has almost 20000 lines
# 5  
Code:
pg=23
lne=0
while read line
do
str="${str}
${line}"
(( lne = lne + 1 ))
if [[ $(( lne % pg )) -eq 0 ]]
then
        echo "$str" | sed -n "/AEADBMP002/,$ p"
        str=""
fi
done < file
[[ -n $str ]] && echo $str | sed -n "/AEADBMP002/,$ p"

Assign the number of lines what you consider as a page to the variable pg
 

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