UNIX for Dummies Questions & Answers

result=[]
count = 0
for i in range(len(a)):
 	if a[i] == b[i]:
 		count += 1
 		result.append(a[i])
print count,result

2 ['a', 'c']

[/tmp]$ cat try.ksh
#! /bin/ksh

haystack="The quick brown fox jumps over the lazy dog"
needle="acefizkjlfsh"

hold=$needle
typeset -L1 bit
match=""

while [[ ${#hold} -gt 0 ]]
do
    bit=$hold
    if [[ $haystack = *$bit* ]] ; then
        if [[ $match != *$bit* ]] ; then
            match=$match$bit
        fi;
    fi;
    hold=${hold#$bit}
done

echo "${#match} - $match"
[/tmp]$ ./try.ksh
11 - acefizkjlsh
[/tmp]$

echo "The quick brown fox jumps over the lazy dog" | fold -1 | sort -u > file1
echo "acefizkjlfsh" | fold -1 | sort -u | egrep -f file1 > file2
echo $(wc -l < file2) [$(paste -s -d, file2)]

11 [a,c,e,f,h,i,j,k,l,s,z]