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String Array

 
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# 1  
Old 11-15-2006
Question String Array
I am having a string with the value:
str="name1, name2, name3, "

I want to traverse the list of elements. How do I loop them?
Last edited by ravikirankethe; 11-15-2006 at 11:22 AM..
# 2  
Old 11-15-2006
One way:
Code:
$ cat sloop
#! /usr/bin/ksh

str="name1, name2, name3, "

while [[ -n $str ]] ; do
        item=${str%%,*}
        str=${str#* }
        echo item = $item
done
exit 0
$ ./sloop
item = name1
item = name2
item = name3

# 3  
Old 11-15-2006
Its easy to loop a string with spaces. So u can substitute the , with a space and then use that new string to loop using for....

str1="value1,value2,value3"
str2=`echo $str1 | tr "," " "`
#there is a space in between the second pair of quotes

for text in $str2
do
echo "$text"
done
justsam
# 4  
Old 11-15-2006
Thanks Perderabo and Justsam.
Justsam logic seems to be bit easy.

Perderabo logic is not working if we have no space in str
str="name1,name2,name3, "
# 5  
Old 11-15-2006
Here's my favorite way of doing this, similar to justsam but without piping $str through tr (UUOtr Smilie )

Code:
str="name1, name2, name3, "

typeset IFS=' ,'
for i in $str
do
    echo $i$i                                                                                                                                                       
done

This User Gave Thanks to tmarikle For This Post:
Amit Kulkarni
# 6  
Old 11-15-2006
Quote:
Originally Posted by ravikirankethe
Perderabo logic is not working if we have no space in str
str="name1,name2,name3, "
Yeah but your original post had ", " which is two characters and there is a superfluous separator ending the string. Sorry for believing what you wrote was accurately describing your problem. Smilie
# 7  
Old 11-15-2006
Code:
str="name1,name2,name3, "

typeset IFS=' ,'
for i in $str
do
    echo $i
done

works with both ", " and ","
 
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