UNIX for Dummies Questions & Answers

Here is the file named tuwork..........

209 200 WZ 6529 SKTNCA01X4X C POI LODI LODI 738 SKTNCA0127T LOD

Here is the scipt.......

cat tuwork |
while
read rva
do
num=`echo $rva | cut -d" " -f1-2`
reg=`echo $rva | cut -c10`
ocn=`echo $rva | cut -c12-15`
x=`echo $rva | cut -c29`
xx=`echo $rva | cut -c30`
cli=`echo $rva | cut -c17-27`
tec=`echo $rva | cut -c31-33`
# rat=`echo $rva | cut -c41-49`
# rax=`echo $rva | cut -c67-41`
# lat=`echo $rva | cut -c51-53`
print "$num $reg $ocn $x $xx $cli $tec" >> tu
done

Here is the ksh -x output..........

+ read rva
+ cat tuwork
+ + cut -d -f1-2
+ print 209 200 WZ 6529 SKTNCA01X4X C POI LODI LODI 738 SKTNCA0127T LOD
num=209 200

The file is......

"209 200 WZ 6529 SKTNCA01X4X C POI LODI LODI 738 SKTNCA0127T LOD"

The output is....

209 200 WZ 6529 SKTNCA01X4X C POI LODI LODI 738 SKTNCA0127T LOD

It's chopping off the extra spaces!!!

How can I stop this? Or is there anything other than echo I can use?

Thanks in advance.

as an example.....

Code:

nawk '{printf("num->[%s%s%s] ocn->[%s]\n", $1, OFS, $2, $4)}' tuwork > tu

try this

Code:

IFS=""
cat f |
while
read rva
do
num=`echo $rva | cut -d" " -f1-2`
reg=`echo $rva | cut -c10`
ocn=`echo $rva | cut -c12-15`
x=`echo $rva | cut -c29`
xx=`echo $rva | cut -c30`
cli=`echo $rva | cut -c17-27`
tec=`echo $rva | cut -c31-33`
# rat=`echo $rva | cut -c41-49`
# rax=`echo $rva | cut -c67-41`
# lat=`echo $rva | cut -c51-53`
print "$num $reg $ocn $x $xx $cli $tec" >> tu
done

echo is echoing correcty.

In other words your string with spaces is interpreted as multiple arguments. Try surrounding the variable with double quotes.