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AwK printf question

 
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# 1  
Old 09-14-2006
Data AwK printf question
Hi,
Does anyone know a easy way to printf $3,$4, ... all the way to the last field in the file? I will need to modify $1 and $2 and then printf modified $1 and $2 and the rest of the fields(which are not changed).
I know I can use NF as the total number of field.
Do I use a for next statement to loop through?

Thanks for your help!
# 2  
Old 09-14-2006
$1="xxxx"
$2="yyyy"
#if you want to print the whole line then do this
print $0
# 3  
Old 09-14-2006
awk
Thank you for your reply.
The things is everytime the file that passed to awk is different.
So I don't know the exact number of columns.
But I only modify $1,$2. There might be over 10 fields after that.
It's really $0 - $1 - $2.
I need to write out any fields after $1 and $2.

Any hint?
# 4  
Old 09-14-2006
use for loop to do that
# 5  
Old 12-10-2007
You don't need a for loop
I know it's been over a year, but maybe someone else will benefit from this.
If you want to print everything but a number of fields, set them to "" (null)

So, to print everything past $2, type:
awk '{ $1=""; $2=""; print $0}' foo.log

This can be shortened to:
awk '{ $1=$2=""; print $0}' foo.log

Be sure never to set $0 to null, because that will nuke your entire string.Smilie
 
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