Grep Question


 
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# 1  
Old 08-18-2006
Question Grep Question

Hello Everybody,

I have files; yyyymmdd.log which the data look like this;

[20/Jun/2006:00:00:56 +0800] "Txid=9426043&MsgTxt=Thankyou&UserId=john&Password=jh2501"
[21/Jun/2006:19:15:56 +0800] "Txid=9426150&MsgTxt=Thankyou&UserId=john&Password=jh2501"
.
.
.
[29/Jun/2006:12:00:26 +0800] "Txid=9426200&MsgTxt=Thankyou&UserId=john&Password=jh2501"

Question 1:
How to grep the data based on date i.e. from 20/Jun/2006 untill 25/Jun/2006?

Question 2:
How to grep specific word only i.e. "Txid=9426043" which the output must be "Txid=9426043" only instead of the whole statement ([20/Jun/2006:00:00:56 +0800] "Txid=9426043&MsgTxt=Thankyou&UserId=john&Password=jh2501")

Question 3:
Normally I do wc-l yyyymmdd.log to check total number of line but how i can create the output file with total number of line e.g. yyyymmdd_"total number of line".log when i run wc .

Appreciate your answers.
# 2  
Old 08-18-2006
Here is a sed solution.

Code:
1. sed -n -e '/20.Jun.2006/,/25.Jun.2006/p' input.txt

2. sed -n -e 's!.*\(Txid=[^&]*\)&.*!\1!p' input.txt

3. line=$(wc -l yyyymmdd.log)
    mv "yyyymmdd.log" "yyyymmdd_$line.log"

# 3  
Old 08-18-2006
for question three u can use this

cat yyyymmdd.log | wc -l > <filename>
# 4  
Old 08-18-2006
Quote:
Originally Posted by slayer666
for question three u can use this

cat yyyymmdd.log | wc -l > <filename>
and why exactly do you need a 'cat' here?
 
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