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help with egrep

 
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# 1  
Old 07-31-2006
help with egrep
I have a file called alert.log containing the following:

WARNING: received KRVX_OPER_CANNOT_SUPPORT
knlldmm: gdbnm=CROOP
knlldmm: objn=23793
knlldmm: objv=1
knlldmm: scn=5189816456
knllgobjinfo: MISSING Streams multi-version data dictionary!!!
knlldmm: gdbnm=FDROP
knlldmm: objn=49385
knlldmm: objv=2
knlldmm: scn=5201332536

Is there any way I can use egrep to pull out only lines 6-10 out of the file? I tried using:

egrep -n -i "knllgobjinfo|knlldmm" alert.log

but that also gives me lines 2-5 which I dont want.
If egrep can't do it, what else can I use that can?

Thanks in advance.
# 2  
Old 08-01-2006
Code:
sed -n '6,10p' alert.log

You can also use regex ranges:
Code:
sed -n '/knllgobjinfo/,/$/p' alert.log

# 3  
Old 08-01-2006
hi jim.First command is printing 6-10 but the second one is printing only 6-7 lines.

Code:
sed -n '/knllgobjinfo/,/$/p' alert.log

# 4  
Old 08-01-2006
typo, my bad.:
(this assumes there is a \n on the end of the last line)
Code:
sed -n '/knllgobjinfo/,$p' alert.log

# 5  
Old 08-01-2006
Thanks a lot, you answered my question, but its not exactly what I was looking, I wasn't as specific as I should have been.

What I really meant is: How can I print to standard output the line beginning with "knllgobjinfo" and its following 4 lines, regardless of where it occurs in the file.

Thanks again.
# 6  
Old 08-01-2006
Dude try following.

sed -n -e '/knllgobjinfo/,+4 p' datafile

Cheers,
Nilesh
# 7  
Old 08-01-2006
nope, this is the error that I get.

sed: 0602-404 Function /knllgobjinfo/,+4 p cannot be parsed.
 
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